Difference between revisions of "Theoretical analysis of 2n accidentals rates"
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[[Production Analysis | go_back]] | [[Production Analysis | go_back]] | ||
==Introduction== | ==Introduction== | ||
| − | Every individual photon pulse may cause any number of neutron-producing reactions, hereafter denoted by <math>n</math>, ranging form zero to "infinity". <math>n</math>, being the number of neutron-producing reactions ''actually'' occurring per pulse, is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces <math>v_{i}</math> neutrons, where <math>v_{i}</math> is the distribution of the number of neutrons produced from a single given neutron-producing reaction. | + | Every individual photon pulse may cause any number of neutron-producing reactions, hereafter denoted by <math>n</math>, ranging form zero to "infinity". <math>n</math>, being the number of neutron-producing reactions ''actually'' occurring per pulse, is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces <math>v_{i}</math> neutrons, where <math>v_{i}</math> is the distribution of the number of neutrons produced from a single given neutron-producing reaction. With a Bremsstrahlung end point of 10.5 MeV, the only energetically possible neutron-producing interactions are 1n-knochout and photofission, so <math>v_{i}</math> is simply the photofission neutron multiplicity with an added contribution from 1n-knockout events. In other words, a 1n-knockout event and a photo-fission event emitting a single neutron are taken to be the same thing. In viewing it this way, the analysis is simplified, and the end result is not changed since 1n=knockouts can only contribute to accidentals. |
Revision as of 02:57, 9 January 2018
Introduction
Every individual photon pulse may cause any number of neutron-producing reactions, hereafter denoted by , ranging form zero to "infinity". , being the number of neutron-producing reactions actually occurring per pulse, is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces neutrons, where is the distribution of the number of neutrons produced from a single given neutron-producing reaction. With a Bremsstrahlung end point of 10.5 MeV, the only energetically possible neutron-producing interactions are 1n-knochout and photofission, so is simply the photofission neutron multiplicity with an added contribution from 1n-knockout events. In other words, a 1n-knockout event and a photo-fission event emitting a single neutron are taken to be the same thing. In viewing it this way, the analysis is simplified, and the end result is not changed since 1n=knockouts can only contribute to accidentals.