Difference between revisions of "July, 6, 2007 Investigations of Geometry Influence on the Fission Fragments Behaviour"

From New IAC Wiki
Jump to navigation Jump to search
Line 5: Line 5:
 
<math>\frac{K}{A}</math> = 0.307075 MeV <math>g^{-1} cm^2</math><br>
 
<math>\frac{K}{A}</math> = 0.307075 MeV <math>g^{-1} cm^2</math><br>
 
<math>T_{max}</math>=61 keV<br>
 
<math>T_{max}</math>=61 keV<br>
<math>\beta</math>=0.033
+
<math>\beta</math>=0.033<br>
 
Incident particle is Ce-140 and as a target we have U-238<br>
 
Incident particle is Ce-140 and as a target we have U-238<br>
Density of Uranium is 19.1 <math>\frac{g}{cm^3}</math>  [http://hypertextbook.com/facts/2006/MichaelMirochnik.shtml]
+
Density of Uranium is 19.1 <math>\frac{g}{cm^3}</math>  [http://hypertextbook.com/facts/2006/MichaelMirochnik.shtml]<br>
 +
 
 +
- <math>\frac{dE}{dx}</math>= 2.66 <math>\frac{MeV}{cm}</math>

Revision as of 21:06, 6 July 2007

1. Theoretical Calculations

Relativistic charged particles lose energy in matter primarily by ionization. The mean rate of energy loss is given by the Bethe_Bloch equation,

- [math]\frac{dE}{dx}[/math]=K[math]z^2\frac{Z}{A}[/math][math]\frac{1}{\beta^2}[/math][[math]\frac{1}{2}\ln\frac{2m_ec^2\beta^2\gamma^2T_{max}}{I^2}[/math] - [math]\beta^2[/math] - [math]\frac{\delta}{2}[/math]]
[math]\frac{K}{A}[/math] = 0.307075 MeV [math]g^{-1} cm^2[/math]
[math]T_{max}[/math]=61 keV
[math]\beta[/math]=0.033
Incident particle is Ce-140 and as a target we have U-238
Density of Uranium is 19.1 [math]\frac{g}{cm^3}[/math] [1]

- [math]\frac{dE}{dx}[/math]= 2.66 [math]\frac{MeV}{cm}[/math]