Difference between revisions of "Finding the Space Between Lead Shots"

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|Mesurements
 
|Mesurements
|V<sub>H2O</sub> = V<sub>sp</sub> <math>cm^3</math>
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|V<sub>H2O</sub> = V<sub>sp</sub> (<math>cm^3</math>)
|V<sub>tot</sub> <math>cm^3</math>
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|V<sub>tot</sub> (<math>cm^3</math>)
 
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|1 ||2600 || 6500  
 
|1 ||2600 || 6500  

Revision as of 17:09, 16 July 2008

Plan 1

By Mass

Lead Shot

1 - Empty box, m 1

2 - Box filled with Lead, m 2

3 - Box filled with Lead and H 2 0, m 3

4 - Box filled with H 2 0, m 4


m Pb = m 2 - m 1

V Pb = (m 2 - m 1) / ρ Pb


m H 2 0 = m 3 - m 2

V H 2 0 = (m 3 - m 2) / ρ Pb = V SP (The space between the lead)

ratio = V Pb / V tot


Plan 2

By Volume

1 - V H 2 0 1 = V tot

2 - V H 2 0 2 = V SP


V Pb = V tot - V SP

R = V Pb / V tot = (V tot - V SP) / V tot => 1 - (V SP / V tot)

Experiment

Plan 1

We had 2 scales to measure the weight. Let's call them scale #1 and scale #2, measurement on them were called weight #1 and Weight respectively.

Mesurements Discriptions masses weight #1 (£) weight #2 (£) Weight AVE (£) Weight AVE (g)
1 Box m 1 3 4 3.5 1587.6
2 Box+Pb m 2 102 103 102.5 46493.2
3 Box+Pb+[math]H_{2}[/math]O m3 105 111 108 48988.0
4 Box+[math]H_{2}[/math]O m4 15 18 16.5 7484.3

Calculations

VPb = (m2 - m1)/ρPb=3959.2 [math]cm^3[/math]

VPb = (m4 - m1)/ρH2O=5896.8 [math]cm^3[/math]

Ratio = VPb/VPb =67%

Plan 2

Mesurements VH2O = Vsp ([math]cm^3[/math]) Vtot ([math]cm^3[/math])
1 2600 6500
2 840 2000