Determining wire-theta correspondence

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5.1.1 Determine a Wire-Theta Correspondence

To associate the hits with the Moller scattering angle theta, the occupancy plots of the drift chamber hits by means of wire numbers and layer must be translated using the physical constraints of the detector. Using the data released for the DC:

DC: Drift Chambers(specs)

DC Geometry(geom)

Table 5.1 Constraints from DC Geometry File

Variable	Measurement	Definition
thtilt	25 degrees	Tilt relative to z
dist2tgt	228.078 cm	Distance from the target to the first guard wire plane along the normal of said plane
th_min	4.694 degrees	Polar angle to the first guard wire’s (in the first guard wire plane) midpoint where the wire mid-point is the intersection of the wire with the chamber mid-plane
wpdist	0.3861 cm	Distance between the wire planes

At 25 degrees above the beam line direction, we can create a line that is perpendicular to the plane of the wires, which are at 65 degrees above the reverse beam line direction. This line will be a perpendicular line with respect to all parallel layers of wires with respect to the initial guard wire plane. We can use this geometry and dist2tgt, which is the distance from the target to the first guard wire plane along the normal of said plane, to calculate other distances.

Figure 5.1.1: The distance and angles which are derived from the angle with respect to the beam line (thtilt) and the distance for the guard wire plane perpendicular bisector(dist2tgt). All distances and angles are for the midplane bisector.

Using trigonometry, we can find the distance along the beam line to the intersection with the initial guard wire plane.

[math]\frac{228.078\ cm}{cos\ 25^{\circ}}=251.6562\ cm[/math]

The wire planes in the DC are parallel to each other and seperated by a constant distance wpdist. The parallel planes of wires are shown in the Figure 5.1.2 below.

Figure 5.1.2: The placement of the different wire planes in the DC as seen

The angle th_min is defined as the polar angle to the first guard wire’s (in the first guard wire plane) midpoint where the wire mid-point is the intersection of the wire with the chamber mid-plane. The first guard wire can be found at 4.694 degrees above the beam line. This position can be taken as the starting position for the wire normal plane.

Figure 5.1.3: The distance and angles based on the 1st location of the lowest guard wire from the beam line.

Using the law of sines, we can find the distance along the x' axis the 1st guard wire is from the beam line.

[math]\frac{251.6562}{sin\ 110.306^{\circ}}=\frac{d}{sin\ 4.694^{\circ}}\Rightarrow d=21.9587\ cm[/math]

Making a right triangle,

[math]21.9587\ cm\ sin\ 65^{\circ}=19.914\ cm\ \hat{x}[/math]

[math]21.9587\ cm\ cos\ 65^{\circ}=9.2802\ cm[/math]

[math]251.6562-9.2802=242.376 cm\ \hat{z}[/math]

Examining the geometry file, we can see that each plane, not just the plane of the sense wires, is separated by a distance of

[math]D=.3861\ cm[/math]

We can use the geometry of the wire placements to find the separation distance between two adjacent sense wires on the same plane

[math]d=4(.3861\ cm)\cos(30^{\circ})=1.337\ cm[/math]

Figure 5.1.4: The distance and angles based on the .

Figure 5.1.5: The distance and angles based on the .

The starting position for sense wires with respect to the first guard wire at midplane, can be found to be at:

[math]2.3166\ cm\ \cos\ 5^{\circ}=2.3078\ cm\ \hat{x}[/math]

[math]2.3166\ cm\ \sin\ 5^{\circ}=.2019\ cm\ \hat{z}[/math]

Since the separation between adjacent sense wires is uniform and at a set angle of 25 degrees with respect to the beam line, we can use this fact to determine the angle theta each wire makes when measured from the vertex.

Figure 5.1.6: The distance and angles based on the .

[math]\Delta\ x=1.337\cos(25^{\circ})cm=1.212cm[/math]

[math]\Delta\ z=-1.337\sin(25^{\circ})cm=-0.5652cm[/math]

The new x and z coordinates for wire 2 can be found using the change in the components

[math]x=x_1+\Delta x[/math] [math]z=z_1+\Delta z[/math]

This can be extended to any point along the same wire plane, starting from the coordinates for wire 1 minus the difference in position to the next wire crossing on the plane.

[math]x_0=x_1-\Delta x[/math] [math]z_0=z_1-\Delta z[/math] [math]x=x_0+\Delta x\times\ n[/math] [math]z=z_0+\Delta z\times\ n[/math]

The angle theta that the wire makes with the vertex is given by

[math]\tan{\theta}=\frac{x_0+\Delta x}{z_0+\Delta z}\Rightarrow \theta=\arctan{\frac{x_0+\Delta x}{z_0+\Delta z}}[/math]

For the values found earlier for the starting position:

[math]\frac{19.9014\ cm\ +2.3078\ cm}{242.3760\ cm+.2019\ cm}=\frac{22.2092\ cm}{242.5779\ cm}=.09155=\tan\ \theta[/math]

[math]\theta(wire\ 1)=\arctan\ .09155=5.2311^{\circ}[/math]

[math]x_0=22.2092-1.212=20.9972\ cm\ \hat{x}[/math] [math]z_0=242.5779+0.5652=243.1431\ cm\ \hat{z}[/math]

[math]x(n)=20.9972+1.212\ n[/math]

[math]z(n)=243.1431-0.5652\ n[/math] [math]\tan{\theta}=\frac{20.9972+n1.212}{243.1431-n0.5652}\Rightarrow \tan{ \theta}=\frac{-959.637}{n - 430.189} - 2.14437 \Rightarrow 430.637 - n = \frac{959.637}{\tan{ \theta}+2.14437}[/math]

[math]\Rightarrow n = \frac{-959.189}{\tan{ \theta}+2.14437}+430.189[/math]

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