T-Channel

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t Channel

The t quantity is known as the square of the 4-momentum transfer

$t \equiv \left({\mathbf P_1^*}- {\mathbf P_1^{'*}}\right)^2=\left({\mathbf P_2^{*}}+ {\mathbf P_2^{'*}}\right)^2$

$t \equiv \left({\mathbf P_1^*}- {\mathbf P_1^{'*}}\right)^2$

$t \equiv \mathbf P_1^{*2}-2 \mathbf P_1^* \mathbf P_1^{'*}+ \mathbf P_1^{'*2}$

$t \equiv 2m_1^2-2E_1^*E_1^{'*}+2 \vec p \ _1^* \vec p \ _1^{'*}$

In the center of mass frame of reference,

$E^* \equiv E_1^*=E_1^{'*} = E_2^*=E_2^{'*} = E_1^*=E_2^*$

and

$|p^*| \equiv | \vec p \ _1^*|=| \vec p \ _1^{'*}| =| \vec p \ _2^*|=| \vec p \ _2^{'*}|$

and $\theta_1$ is the angle between $\vec p \ _1^*$ and $\vec p \ _1^{'*}$

$t \equiv 2m_1^*-2E_1^{*2}+2 |p |^{*2}cos\ \theta$

Using the relativistic term for Energy

$E^2=\vec p \ ^2+m^2$

$t \equiv -2 p \ _1^{*2}(1-cos\ \theta)$

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$\textbf{\underline{Navigation}}$

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