EG1 Teleconferences DeltaDoverD
15-1-09
Electron-Pion COntamination Estimate
The number of photons produced per unit path length of a particle with charge ze and per unit energy interval of the photons is proportional to the sine of the Cherenkov angle[1]
after deriving the Taylor expansion of our function and considering only the first two terms, we get
The gas used in the CLAS Cerenkov counter is perfluorobutane
with index of refraction equal to 1.00153.
Electrons
The calculation of the number of photoelectrons emitted by electrons is shown below.
Electron mass
The Hall B cherenkov detector is m thick radiator. We assume the PMTs used to collect light have a constant quantum efficiency of 8% for photons with wavelength between 300 and 600 nm.
=
- For the number of photoelectrons we have the following
That means the number of photoelectrons should be about 13.
Used file dst27095_05.B00 energy=5.7GeV and torus=2250(B>0). Target NH3
Pions( )
The threshold energy for pions is ~2.5 GeV and for electrons 9 MeV.
- Example for
where
The Hall B cherenkov detector is
m thick radiator. We assume the PMTs used to collect light have a constant quantum efficiency of 8% for photons with wavelength between 300 and 600 nm.
=
- For the number of photons we have the following(for pions)
Used file dst27095_05.B00 energy=5.7GeV and torus=2250(B>0). Target NH3
CLAS Cherenkov signal
Electrons
The cherenkov signal measured in CLAS for particles identified as electrons by the tracking algorithm is shown below. There are two distributions present. One distribution is centered around 1.5 PEs and the second distribution is at 8 PEs when two gaussians and a Landau distribution are combined and fit to the spectrum. As we will show below, the first peak is due to the misidentification of a negative pion as an electron.
- PE Fit equation
File:Gaussian fitting function.pdf
C.Lanczos, SIAM Journal of Numerical Analysis B1 (1964), 86. File:C.Lanczos SIAM Journal of Numerical Analysis B1 1964 86.pdf
normalized fitting functions
Landau and Landaun difference
for me
//__[2] [3] ____________________________________________________________________________ Double_t TMath::Landau(Double_t x, Double_t mpv, Double_t sigma, Bool_t norm) { // The LANDAU function with mpv(most probable value) and sigma. // This function has been adapted from the CERNLIB routine G110 denlan. // If norm=kTRUE (default is kFALSE) the result is divided by sigma static Double_t p1[5] = {0.4259894875,-0.1249762550, 0.03984243700, -0.006298287635, 0.001511162253}; static Double_t q1[5] = {1.0 ,-0.3388260629, 0.09594393323, -0.01608042283, 0.003778942063}; static Double_t p2[5] = {0.1788541609, 0.1173957403, 0.01488850518, -0.001394989411, 0.0001283617211}; static Double_t q2[5] = {1.0 , 0.7428795082, 0.3153932961, 0.06694219548, 0.008790609714}; static Double_t p3[5] = {0.1788544503, 0.09359161662,0.006325387654, 0.00006611667319,-0.000002031049101}; static Double_t q3[5] = {1.0 , 0.6097809921, 0.2560616665, 0.04746722384, 0.006957301675}; static Double_t p4[5] = {0.9874054407, 118.6723273, 849.2794360, -743.7792444, 427.0262186}; static Double_t q4[5] = {1.0 , 106.8615961, 337.6496214, 2016.712389, 1597.063511}; static Double_t p5[5] = {1.003675074, 167.5702434, 4789.711289, 21217.86767, -22324.94910}; static Double_t q5[5] = {1.0 , 156.9424537, 3745.310488, 9834.698876, 66924.28357}; static Double_t p6[5] = {1.000827619, 664.9143136, 62972.92665, 475554.6998, -5743609.109}; static Double_t q6[5] = {1.0 , 651.4101098, 56974.73333, 165917.4725, -2815759.939}; static Double_t a1[3] = {0.04166666667,-0.01996527778, 0.02709538966}; static Double_t a2[2] = {-1.845568670,-4.284640743}; if (sigma <= 0) return 0; Double_t v = (x-mpv)/sigma; Double_t u, ue, us, den; if (v < -5.5) { u = TMath::Exp(v+1.0); if (u < 1e-10) return 0.0; ue = TMath::Exp(-1/u); us = TMath::Sqrt(u); den = 0.3989422803*(ue/us)*(1+(a1[0]+(a1[1]+a1[2]*u)*u)*u); } else if(v < -1) { u = TMath::Exp(-v-1); den = TMath::Exp(-u)*TMath::Sqrt(u)* (p1[0]+(p1[1]+(p1[2]+(p1[3]+p1[4]*v)*v)*v)*v)/ (q1[0]+(q1[1]+(q1[2]+(q1[3]+q1[4]*v)*v)*v)*v); } else if(v < 1) { den = (p2[0]+(p2[1]+(p2[2]+(p2[3]+p2[4]*v)*v)*v)*v)/ (q2[0]+(q2[1]+(q2[2]+(q2[3]+q2[4]*v)*v)*v)*v); } else if(v < 5) { den = (p3[0]+(p3[1]+(p3[2]+(p3[3]+p3[4]*v)*v)*v)*v)/ (q3[0]+(q3[1]+(q3[2]+(q3[3]+q3[4]*v)*v)*v)*v); } else if(v < 12) { u = 1/v; den = u*u*(p4[0]+(p4[1]+(p4[2]+(p4[3]+p4[4]*u)*u)*u)*u)/ (q4[0]+(q4[1]+(q4[2]+(q4[3]+q4[4]*u)*u)*u)*u); } else if(v < 50) { u = 1/v; den = u*u*(p5[0]+(p5[1]+(p5[2]+(p5[3]+p5[4]*u)*u)*u)*u)/ (q5[0]+(q5[1]+(q5[2]+(q5[3]+q5[4]*u)*u)*u)*u); } else if(v < 300) { u = 1/v; den = u*u*(p6[0]+(p6[1]+(p6[2]+(p6[3]+p6[4]*u)*u)*u)*u)/ (q6[0]+(q6[1]+(q6[2]+(q6[3]+q6[4]*u)*u)*u)*u); } else { u = 1/(v-v*TMath::Log(v)/(v+1)); den = u*u*(1+(a2[0]+a2[1]*u)*u); } if (!norm) return den; return den/sigma; }
Fitting the Histograms
root [13] e_numb_of_photoelectrons->Draw();
root [2] g3= new TF1("g3","gaus(0)+landau(3)+gaus(6)",0,20);
To get fit parameters for g3 we should fit individually each of them(gaus(0),landau(3),gaus(6))
root [3] g3->SetParameters(2.3e3,8,8.1,8.6e+3,8.6e-1,1.6,8.6e+3,8.6e-1,1.6,8.6e3)
root [11] e_numb_of_photoelectrons->Fit("g3","R+");
- e_Momentum_vs_Number_of_Photoelectrons
The flag cut applied on the number of photoelectrons means that in CLAS detector instead of 5 superlayers were used 6 of them in track fit. As one can see from the histograms of the Number of photoelectrons, the cut on flag does not have effect on the peak around 1.5phe and decreases the number of entries by 37.17 %. The peak is due to a high energy pions(>2.5GeV), which have enough momentum to emit Cherenkov light and also because of the bad collection of light, there are a particular polar and azimuthal combination of angles where The Cherencov Detector cannot receive emitted light. .
- Number of photoelectrons
Data | |||
---|---|---|---|
Table: Cherenkov fit values
Distributions | amplitude | mean | width | amplitude | mean | width |
---|---|---|---|---|---|---|
without cuts | with cut(flag>10) | |||||
gauss(0) | p0=2144+/-44.0 | p1=5.342+/-0.343 | p2=7.761+/-0.188 | p0=1580+/-8.1 | p1=3.75+/-0.06 | p2=8.486+/-0.042 |
landau(3) | p3=4.349e+04+/-2894 | p4=1.049+/-0.026 | p5=0.2197+/-0.0257 | p3=8600+/-3648.7 | p4=-3.861+/-1.414 | p5=-4.88+/-1.41 |
gauss(6) | p6=4960+/-270.6 | p7=0.7345+/-0.0983 | p8=0.8885+/-0.0594 | p6=6219+/-54.2 | p7=1.088+/-0.006 | p8=0.6037+/-0.0052 |
When flag cut(flag>10 cut means that 6 superlayers were used in track fit) was applied the number of entries decreased by 37.17 % and the mean value for the number of photoelectrons is about 7-8. After 5<nphe<15 cut, the number of entries decreased by 66.63 %.The mean value of the nphe is ~9 which agrees with theory(mean value ~13).
Experiment | B>0 | without cuts | flag>10 | 5<nphe<15 | 5<nphe<15 and flag>10 |
---|---|---|---|---|---|
Pions( )
- _Momentum_vs_Number_of_Photons
After e_flag>10 cut, the number of entries decreased by 30.45 % and the mean value for the number of photons is ~9
Experiment | B>0 | without cuts | e_flag>10 | 0<e_nphe<5 | 0<nphe<5 and e_flag>10 |
---|---|---|---|---|---|
Electron-pion contamination
Osipenko's CLAS Note 2004-20 File:CLAS Note-2004-020.pdf
- EC_tot/P_vs_Number_of_Photoelectrons and EC_inner/P_vs_Number_of_Photoelectrons
Two types of cuts were applied on the distributions below, one on the energy deposited to the inner calorimeter
without cut | _vs_nphe( ) | _vs_nphe ( ) | _vs_nphe( ) |
---|---|---|---|
_vs_nphe( ) | _vs_nphe( and ) | _vs_nphe ( and ) |
---|---|---|
From the EC_tot/P_vs_Number_of_Photoelectrons histogram one can see that the released energy fraction( ) at ~1.5 nphe peak is much smaller than it should be for electrons. In conclusion, the ~1.5 nphe peak is produced by the tail of negatively charged particles(pions). To eliminate negatively charged pions cut is applied on Calorimeter. After the cut was applied the number of entries decreased by ~33.47%.
Pion contamination in the electron sample (without cuts) =
with cut( | )with cut( | )with cuts( | and )|
---|---|---|---|
Distributions | amplitude | mean | width | amplitude | mean | width | amplitude | mean | width |
---|---|---|---|---|---|---|---|---|---|
with cut( | )with cut( | )with cuts( | and )|||||||
gauss(0) | p0=1919+/-17.8 | p1=3.593+/-0.233 | p2=8.269+/-0.134 | p0=2025+/-9.4 | p1=3.44+/-0.05 | p2=8.442+/-0.037 | p0=1732+/-8.4 | p1=3.886+/-0.050 | p2=8.069+/-0.037 |
landau(3) | p3=8600+/-1.4 | p4=-3.063+/-1.414 | p5=-7.138+/-0.000 | p3=8600+/-3648.7 | p4=-3.092+/-1.414 | p5=-10.91+/-0.000 | p3=8600+/-5160.0 | p4=-2.821+/-1.414 | p5=-7.986+/-1.414 |
gauss(6) | p6=5568+/-69.1 | p7=1.164+/-0.006 | p8=0.543+/-0.008 | p6=5773+/-76.6 | p7=1.162+/-0.008 | p8=0.5562+/-0.0052 | p6=4301+/51.3 | p7=1.189+/-0.008 | p8=0.5299+/-0.0059 |
e_numb_of_photoelectrons with the following cuts
, . To eliminate the photons produced by the negatively charged pions was used the cut on the momentum e_momentum<3 GeV. Because the high energy pions are able to produce photons, which are misidentified with photoelectrons.