Difference between revisions of "Differential Cross-Section"
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| − | + | Calculating the parts: | |
| − | + | <center><math>\frac{t^2}{u^2}=\frac{-2p^{*2}\left(1-\cos{\theta}\right\right)^2}{-2p^{*2}\left(1+\cos{\theta}\right\right)^2}=\frac{4p^{*2}\left(1-\cos{\theta}\right)^2}{4p^{*2}\left(1+\cos{\theta}\right)^2}=\tan^4{\frac{\theta}{2}}</math></center> | |
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| − | <center><math>\frac{ | ||
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