Difference between revisions of "Limit of Energy in Lab Frame"
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<center><math>t=-2p_1^{*2}(1- \cos \theta_{1\ 1'})=-2p_2^{*2}(1-\cos \theta_{2\ 2'})</math></center> | <center><math>t=-2p_1^{*2}(1- \cos \theta_{1\ 1'})=-2p_2^{*2}(1-\cos \theta_{2\ 2'})</math></center> | ||
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+ | The maximum momentum is transfered at 90 degrees, i.e. <math>\cos 90^{circ}=0</math> | ||
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+ | <center><math>t=-2p_1^{*2}</math></center> | ||
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+ | This can be rewritten again using the relativistic energy relation <math>E^2=m^2+p^2</math> | ||
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+ | <center><math>t=-2(m^{2}-E_1^{*2})=-2(m^{2}-E_2^{*2})</math></center> | ||
Revision as of 15:37, 15 March 2018
The t quantity is known as the square of the 4-momentum transfer
In the CM Frame
where and is the angle between the before and after momentum in the CM frame
Using the relativistic relation this reduces to
The maximum momentum is transfered at 90 degrees, i.e.
This can be rewritten again using the relativistic energy relation
In the Lab Frame
with
and