Difference between revisions of "Finding the Space Between Lead Shots"
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Calculations | Calculations | ||
| − | V<sub>Pb</sub> = (m<sub>2</sub> -m<sub>1</sub>)/ρ<sub>Pb</sub>=3959.2 <math>cm^3</math> | + | V<sub>Pb</sub> = (m<sub>2</sub> - m<sub>1</sub>)/ρ<sub>Pb</sub>=3959.2 <math>cm^3</math> |
| + | |||
| + | V<sub>tot</sub> = (m<sub>4</sub> - m<sub>1</sub>)/ρ<sub>H2O</sub>=5896.8 <math>cm^3</math> | ||
=== Plan 2=== | === Plan 2=== | ||
Revision as of 17:03, 16 July 2008
Plan 1
By Mass
1 - Empty box, m 1
2 - Box filled with Lead, m 2
3 - Box filled with Lead and H 2 0, m 3
4 - Box filled with H 2 0, m 4
m Pb = m 2 - m 1
V Pb = (m 2 - m 1) / ρ Pb
m H 2 0 = m 3 - m 2
V H 2 0 = (m 3 - m 2) / ρ Pb = V SP (The space between the lead)
ratio = V Pb / V tot
Plan 2
By Volume
1 - V H 2 0 1 = V tot
2 - V H 2 0 2 = V SP
V Pb = V tot - V SP
R = V Pb / V tot = (V tot - V SP) / V tot => 1 - (V SP / V tot)
Experiment
Plan 1
We had 2 scales to measure the weight. Let's call them scale #1 and scale #2, measurement on them were called weight #1 and Weight respectively.
| Mesurements | Discriptions | masses | weight #1 (£) | weight #2 (£) | Weight AVE (£) | Weight AVE (g) |
| 1 | Box | m 1 | 3 | 4 | 3.5 | 1587.6 |
| 2 | Box+Pb | m 2 | 102 | 103 | 102.5 | 46493.2 |
| 3 | Box+Pb+O | m3 | 105 | 111 | 108 | 48988.0 |
| 4 | Box+O | m4 | 15 | 18 | 16.5 | 7484.3 |
Calculations
VPb = (m2 - m1)/ρPb=3959.2
Vtot = (m4 - m1)/ρH2O=5896.8