Limit of Energy in Lab Frame: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 20: | Line 20: | ||
<center><math>{\mathbf P_1^{*2}}+ {\mathbf P_1^{'*2}}-2 {\mathbf P_1^*} {\mathbf P_1^{'*}}={\mathbf P_2^{*2}}+ {\mathbf P_2^{'*2}}-2 {\mathbf P_2^*} {\mathbf P_2^{'*}}</math></center> | <center><math>t={\mathbf P_1^{*2}}+ {\mathbf P_1^{'*2}}-2 {\mathbf P_1^*} {\mathbf P_1^{'*}}={\mathbf P_2^{*2}}+ {\mathbf P_2^{'*2}}-2 {\mathbf P_2^*} {\mathbf P_2^{'*}}</math></center> | ||
<center><math>2m^2-2E_1^*E_1^{'*}+2 \vec p_1^* \vec p_1^{'*}=2m^2-2E_2^*E_2^{'*}+2 p_2^* p_2^{'*}</math></center> | <center><math>t=2m^2-2E_1^*E_1^{'*}+2 \vec p_1^* \vec p_1^{'*}=2m^2-2E_2^*E_2^{'*}+2 p_2^* p_2^{'*}</math></center> | ||
<center><math>2m^2-2E_1^{*2}+2 \left | p_1^{*2}\right | \cos \theta_{1\ 1'}=2m^2-2E_2^{*2}+2 \left | p_2^{*2}\right | \cos \theta_{2\ 2'}</math></center> | <center><math>t=2m^2-2E_1^{*2}+2 \left | p_1^{*2}\right | \cos \theta_{1\ 1'}=2m^2-2E_2^{*2}+2 \left | p_2^{*2}\right | \cos \theta_{2\ 2'}</math></center> | ||
where <math>\theta_{1\ 1'}</math> is the angle between the before and after momentum in the CM frame | where <math>\theta_{1\ 1'}</math> and <math>\theta_{2\ 2'}</math>is the angle between the before and after momentum in the CM frame | ||
| Line 36: | Line 36: | ||
<center><math>-2p_1^{*2}+2 \left | p_1^{*2}\right | \cos \theta_{1\ 1'}=-2p_2^{*2}+2 \left | p_2^{*2}\right | \cos \theta_{2\ 2'}</math></center> | <center><math>t=-2p_1^{*2}+2 \left | p_1^{*2}\right | \cos \theta_{1\ 1'}=-2p_2^{*2}+2 \left | p_2^{*2}\right | \cos \theta_{2\ 2'}</math></center> | ||
<center><math>t=-2p_1^{*2}(1- \cos \theta_{1\ 1'})=-2p_2^{*2}(1-\cos \theta_{2\ 2'})</math></center> | |||
Revision as of 15:31, 15 March 2018
The t quantity is known as the square of the 4-momentum transfer
In the CM Frame
where [math]\displaystyle{ \theta_{1\ 1'} }[/math] and [math]\displaystyle{ \theta_{2\ 2'} }[/math]is the angle between the before and after momentum in the CM frame
Using the relativistic relation [math]\displaystyle{ E^2=m^2+p^2 }[/math] this reduces to
In the Lab Frame
with [math]\displaystyle{ p_2=0 }[/math]
and [math]\displaystyle{ E_2=m }[/math]
[math]\displaystyle{ \vartriangleleft }[/math] [math]\displaystyle{ \triangle }[/math] [math]\displaystyle{ \vartriangleright }[/math]