Difference between revisions of "Theoretical analysis of 2n accidentals rates"
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==Accidentals== | ==Accidentals== | ||
− | First, I seek to find the probability of detecting a specific pair of neutrons from this pulse. Let the pair be an accidental, meaning that the two detected neutrons were produced in separate interactions. The probability of detecting a specific neutron accidental pair, given that <math>v_1...v_n</math> neutron producing interactions have occurred: | + | First, I seek to find the probability of detecting a specific pair of neutrons from this pulse. Let the pair be an accidental, meaning that the two detected neutrons were produced in separate interactions. The probability of detecting a specific neutron accidental pair, given that <math>v_1...v_n</math> neutron producing interactions have occurred, is given by: |
− | :<math>p(d_id_j|,v_1...v_n)</math> | + | :<math>p(d_id_j|,v_1...v_n) = p(d_id_j)</math> |
+ | :where, | ||
+ | ::<math>d_{i,j}</math> is the probability of detecting both neutrons of interest. | ||
Revision as of 04:51, 20 January 2018
Introduction
A given photon pulse may cause multiple neutron-producing reactions, ranging from zero to "infinity" reactions. The number of neutron-producing reactions in a pulse is hereafter denoted by
. Being the number of neutron-producing reactions actually occurring per pulse, is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction is said to produce correlated neutrons, where the random variable is the distribution of the number of neutrons produced in a single neutron-producing reaction. Each of the are independent and identically distributed random variables, so the purpose of the subscript is to distinguish between several distinct neutron-producing interactions which may occur in a single pulse.The beam has a Bremsstrahlung end point of 10.5 MeV, which energetically allows for only two possible neutron-producing interactions, 1n-knochout and photofission. Thus,
is equal to the photofission neutron multiplicity plus a contribution at from 1n-knockout events. The analysis that follows does not need to distinguish between 1n-knockout events and photofission events that emit a single neutron. In both cases, a single neutron is emitted and is uncorrelated with all and any other neutrons.Variable reference
variable | Description |
---|---|
A random variable for the number of neutron producing reactions occurring in a single pulse. | |
A random variable for the number of correlated neutrons produced by a single neutron-producing reaction in a given pulse. | |
A random variable with the same distribution as | . The index only distinguishes between distinct and independent instances of .|
Poissonian mean for the number of neutron-producing interactions per pulse. |
Section Title
Consider a pulse in which
neutron-producing interactions occurred, where each individual reaction produces correlated neutrons, where ranges from 1 to . This event is denoted as, , and its probability by the expression, .
Accidentals
First, I seek to find the probability of detecting a specific pair of neutrons from this pulse. Let the pair be an accidental, meaning that the two detected neutrons were produced in separate interactions. The probability of detecting a specific neutron accidental pair, given that
neutron producing interactions have occurred, is given by:- where,
- is the probability of detecting both neutrons of interest.