S-Channel: Difference between revisions

From New IAC Wiki
Jump to navigation Jump to search
Vanwdani (talk | contribs)
Vanwdani (talk | contribs)
Line 25: Line 25:


This gives,
This gives,
<center><math>s \equiv m_1^{2}+2 \mathbf P_1^* \mathbf P_2^*+  m_2^{2}</math></center>
<center><math>s \equiv m_1^{2}+2 \mathbf P_1^* \mathbf P_2^*+  m_2^{2} \equiv m_1^{'2}+2 \mathbf P_1^{'*} \mathbf P_2^{'*}+  m_2^{'2}</math></center>




Line 32: Line 32:




<center><math>s \equiv  2m^{2}+2 \mathbf P_1^* \mathbf P_2^*</math></center>
<center><math>s \equiv  2m^{2}+2 \mathbf P_1^* \mathbf P_2^* \equiv  2m^{2}+2 \mathbf P_1^{'*} \mathbf P_2^{'*}</math></center>


Using the relationship
Using the relationship

Revision as of 15:32, 24 June 2017

[math]\displaystyle{ \textbf{\underline{Navigation}} }[/math]

[math]\displaystyle{ \vartriangleleft }[/math] [math]\displaystyle{ \triangle }[/math] [math]\displaystyle{ \vartriangleright }[/math]

s Channel

The s quantity is known as the square of the center of mass energy (invariant mass)

[math]\displaystyle{ s \equiv \left({\mathbf P_1^*}+ {\mathbf P_2^{*}}\right)^2=\left({\mathbf P_1^{'*}}+ {\mathbf P_2^{'*}}\right)^2 }[/math]



[math]\displaystyle{ s \equiv \mathbf P_1^{*2}+2 \mathbf P_1^* \mathbf P_2^*+ \mathbf P_2^{*2} \equiv \mathbf P_1^{'*2}+2 \mathbf P_1^{'* }\mathbf P_2^{'*}+ \mathbf P_2^{'*2} }[/math]


As shown earlier, the square of a 4-momentum is


[math]\displaystyle{ \mathbf P^{2} \equiv m^2 }[/math]

This gives,

[math]\displaystyle{ s \equiv m_1^{2}+2 \mathbf P_1^* \mathbf P_2^*+ m_2^{2} \equiv m_1^{'2}+2 \mathbf P_1^{'*} \mathbf P_2^{'*}+ m_2^{'2} }[/math]


For the case [math]\displaystyle{ m_1=m_2=m }[/math]


[math]\displaystyle{ s \equiv 2m^{2}+2 \mathbf P_1^* \mathbf P_2^* \equiv 2m^{2}+2 \mathbf P_1^{'*} \mathbf P_2^{'*} }[/math]

Using the relationship


[math]\displaystyle{ \mathbf P_1 \cdot \mathbf P_2 = E_{1}E_{2}-(\vec p_1 \vec p_2) }[/math]


[math]\displaystyle{ s \equiv 2m^2+2(E_1^*E_2^*-\vec p \ _1^* \vec p \ _2^*) }[/math]


In the center of mass frame of reference,

[math]\displaystyle{ E_1^*=E_2^* \quad and \quad \vec p \ _1^*=-\vec p \ _2^* }[/math]


[math]\displaystyle{ s_{CM} \equiv 2m^2+2E_1^{*2}+2\vec p_1 \ ^{*2} }[/math]


Using the relativistic energy equation

[math]\displaystyle{ E^2 \equiv \vec p_1 \ ^2+m^2 }[/math]


[math]\displaystyle{ s_{CM} \equiv 2m^2+2m^2+2\vec p_1 \ ^{*2}+\vec p_1 \ ^{*2}) }[/math]


[math]\displaystyle{ s_{CM}=4(m^2+\vec p_1 \ ^{*2})=(2E_1^*)^{2} }[/math]




[math]\displaystyle{ \textbf{\underline{Navigation}} }[/math]

[math]\displaystyle{ \vartriangleleft }[/math] [math]\displaystyle{ \triangle }[/math] [math]\displaystyle{ \vartriangleright }[/math]