Difference between revisions of "PAA ResultsFromTheIAC"
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A 20 MeV electron was used to make a bremsstrahlung beam that impinged HEU disks | A 20 MeV electron was used to make a bremsstrahlung beam that impinged HEU disks | ||
+ | |||
+ | Below is an uncalibrated spectrum using Thorium rods on Detector D. Lines should appear at 238.8,338.8, 511, 583.4, 911.2, and 2614.6 keV | ||
+ | |||
+ | |||
+ | |||
+ | {| border="3" cellpadding="5" cellspacing="0" | ||
+ | | Channel|| Energy (keV) | ||
+ | |- | ||
+ | |236 || 238.8 | ||
+ | |- | ||
+ | |334 || 338.8 | ||
+ | |- | ||
+ | |505 || 511 | ||
+ | |- | ||
+ | |576 || 583 | ||
+ | |- | ||
+ | |901 || 911.2 | ||
+ | |- | ||
+ | |2586 || 2614.6 | ||
+ | |} | ||
+ | |||
+ | slope=1.0108 +/- 0.000328475 | ||
+ | y-intercept=0.6533 +/- 0.385247 | ||
+ | |||
+ | MPA->Draw("0.6533+1.0108*evt.Chan>>(8000,0,8000)"); | ||
[[PAA_Research]] | [[PAA_Research]] |
Revision as of 22:28, 26 September 2016
Scotch Tape -vs- Kapton tape
A 20 MeV electron was used to make a bremsstrahlung beam that impinged a sample of regular Scotch Tape and Kapton tape. Both tapes had similar areas of 2.5 x 3 cm. The Kapton had twice as much mass as the Scotch (0.1247 g -vs 0.0699 g).
The scotch taper became brittle after 4 hours of irradiation on the 25 N machine.
Below is an uncalibrated spectrum using Thorium rods. Lines should appear at 238.8,338.8, 511, 583.4, 911.2, and 2614.6 keV
Channel | Energy (keV) |
242 | 238.8 |
342 | 338.8 |
514 | 511 |
586 | 583 |
914 | 911.2 |
2617 | 2614.6 |
slope=1.0003 +/- 0.000156023 y-intercept=-3.12645 +/- 0.185346
MPA->Draw("-3.12645+1.0003*evt.Chan>>(8000,0,8000)");
Scotch tape run was 6663.4 seconds long (MPA->Draw("-3.12645+1.0003*evt.Chan>>NScotchTape(8000,0,8000)","0.00015");)
Kapton Tape run was 488.44 seconds long (MPA->Draw("-3.12645+1.0003*evt.Chan>>NKaptonTape(8000,0,8000)","0.0020473344");)
HEU disks
A 20 MeV electron was used to make a bremsstrahlung beam that impinged HEU disks
Below is an uncalibrated spectrum using Thorium rods on Detector D. Lines should appear at 238.8,338.8, 511, 583.4, 911.2, and 2614.6 keV
Channel | Energy (keV) |
236 | 238.8 |
334 | 338.8 |
505 | 511 |
576 | 583 |
901 | 911.2 |
2586 | 2614.6 |
slope=1.0108 +/- 0.000328475 y-intercept=0.6533 +/- 0.385247
MPA->Draw("0.6533+1.0108*evt.Chan>>(8000,0,8000)");