Difference between revisions of "Lab 9 TF EIM"
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[[File:TF_EIM_Lab9a.png | 200 px]] | [[File:TF_EIM_Lab9a.png | 200 px]] | ||
#Select <math>R_1</math> and <math>R_2</math> such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at <math>V_{out}</math> is 3 V when there is no input pulse. | #Select <math>R_1</math> and <math>R_2</math> such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at <math>V_{out}</math> is 3 V when there is no input pulse. | ||
− | #Select a capacitor <math>(C)</math> to form a differentiating circuit for the pulse from the signal generator. Hint: <math>R_{12}C \ll \tau</math>. | + | #Select a capacitor <math>(C)</math>and a pulse width <math>\tau</math> to form a differentiating circuit for the pulse from the signal generator. Hint: <math>R_{12}C \ll \tau</math>. |
#plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time using your scope observations. (20 pnts) | #plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time using your scope observations. (20 pnts) | ||
− | # Now add the diode circuit from part 1 to prevent <math>V_{out}</math> from rising above +5 V. | + | # Now add the diode circuit from part 1 to prevent <math>V_{out}</math> from rising above +5 V. Sketch the new circuit below. |
− | #plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time with the diode circuit you added using your scope observations. (20 pnts) | + | #plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts) |
=Questions= | =Questions= |
Latest revision as of 02:55, 23 February 2011
Lab 9: Diode Circuits
Clipping Circuit
1.) Construct the circuit shown below using a silicon diode.
2.) Use a sine wave generator to drive the circuit so
where V and = 1kHz. (20 pnts)3.)Based on your observations using a oscilloscope, sketch the voltages
and as a function of time.4.)Do another sketch for
= 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)Differentiating Circuit with clipping
- Construct the circuit below.
- Select and such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at is 3 V when there is no input pulse.
- Select a capacitor and a pulse width to form a differentiating circuit for the pulse from the signal generator. Hint: .
- plot and as a function of time using your scope observations. (20 pnts)
- Now add the diode circuit from part 1 to prevent from rising above +5 V. Sketch the new circuit below.
- plot and as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)
Questions
- Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)