2-Neutron Correlation Setup Stuff

Big Detector Solid Angle Calculations

MCNPX Simulation

• 14 MeV neutron source, emitted isotropically ([math]\displaystyle{ 4\pi }[/math])
  
• Detector placed 1m away from source
  

• face of the detector is 15.24cm x 76.2cm, and 3.6cm deep
  

The solid angle can be found from the number of particles hitting the detector as:
[math]\displaystyle{ \Delta \Omega = 4\pi*\frac{hits}{hits + misses} }[/math]

Results

• Out of 1E9 neutrons generated, 8618287 neutrons hit the detector
  • [math]\displaystyle{ \Delta \Omega = 0.108 Sr }[/math]
    • if the detector is placed 70cm away from the source, [math]\displaystyle{ \Delta \Omega = 0.207 Sr }[/math]
    • if the detector is placed 65cm away from the source, [math]\displaystyle{ \Delta \Omega = 0.236 Sr }[/math]

• As a test to verify our results
  • We change the detector size to 2cm by 2cm and used 1E9 neutrons again
  • 32061 neutrons struck the detector
  • [math]\displaystyle{ \Delta \Omega = 0.0004 Sr }[/math]

• And, as a second test to verify our results
  • We change the detector size to 1cm by 1cm and used 1E9 neutrons again
  • 7965 neutrons struck the detector
  • [math]\displaystyle{ \Delta \Omega = 0.0001 Sr }[/math]

Now, what neutron singles rate into the detector should correspond to 1 fission per pulse?

• If we have 1 fission per pulse and each fission emits on average 2.3 neutrons, we should expect 2.3 neutrons/pulse
• The number of neutrons hitting the detector per pulse is found as [math]\displaystyle{ 2.3*\frac{\Delta \Omega}{4\pi} }[/math]
  • @ 1 meter => 0.0198 neutrons hitting the detector per pulse
  • @ 70 cm => 0.0379 neutrons hitting the detector per pulse
• Taking into account the efficiency of the detector [math]\displaystyle{ \epsilon_0 }[/math], the number detected per pulse can be found as [math]\displaystyle{ 2.3*\frac{\Delta \Omega}{4\pi}*\epsilon_0 }[/math]
  • @ 1 meter from source => ([math]\displaystyle{ 0.0198*\epsilon_0=0.0198*0.17=0.003 }[/math]) neutrons detected per pulse
  • @ 70 cm from source => ([math]\displaystyle{ 0.0379*\epsilon_0=0.0379*0.17=0.006 }[/math]) neutrons detected per pulse

Neutron and Photon Flux Through Lead

Using MCNPX, a simulation was done to determine how much of the neutrons and photons from the target will be blocked by various thickness of lead. With a monochromatic pencil beam of incident particles, the following results illustrate how much of the initial beam actually made it through the lead.

Neutron and Photon Flux Through Concrete

Detector Cross-Talk

Using MCNPX, I am trying to simulated the cross-talk we could expect between the big detectors. I used a fission neutron energy spectrum given in MCNPX, shown below.

These neutrons are incident upon a plastic scintillator and I will look at the neutrons and photons coming out of the scintillator's sides perpendicular to the incident beam. The first case I will look at is where the detectors are placed with only polyethylene between them, as illustrated below.

This results in a neutron and photon energy spectrum as follows.

The next case I will look at is where we put a layer of lead between the polyethylene between the detectors, as shown in the schematic below.

The results for this setup using 1 inch of lead between the detectors is as follows.

And, the results for this setup using 2 inches of lead between the detectors is as follows.

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