Difference between revisions of "ArCO2 IonizationPhysics"
Jump to navigation
Jump to search
(New page: <math>\bar{E}=</math> 27 eV = average energy to ionize and electron in an Argon Atom <math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced) |
|||
(6 intermediate revisions by one other user not shown) | |||
Line 1: | Line 1: | ||
+ | A Min Ion Particle traversing Ar gas at 1 atm ionizes 22 atoms/cm Primary and 94-100 Total per cm. The Primary is an ionization from the incident particle, Total includes ionization from secondaries. | ||
− | <math>\bar{E}=</math> 27 eV = average energy to ionize | + | <math>\bar{E}=</math> 27 eV = average energy to ionize an electron in an Argon Atom |
<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced | <math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced | ||
+ | |||
+ | Quenching Gas: | ||
+ | |||
+ | 1.) reduces the influence of the positive ions creates on the photoelectron signal: The excited Ar+ atoms emit photon in the UV range which are absorbed by the quenching gas | ||
+ | |||
+ | 2.)Collisions with the quenching gas will neutralize the Ar+ ions. When the quenched gas, having an electron remove by the Ar+ collision, reaches the cathode and collects an electron, most of the energy goes into dissociation of the Quench gas. | ||
+ | |||
+ | If the quech gas is CH4 then | ||
+ | |||
+ | CH4+ <math>\Rightarrow</math> H2 + CH2 | ||
+ | |||
+ | ;Argon Escape peak: | ||
+ | |||
+ | :You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits an X-ray which excapes the chamber. | ||
+ | |||
+ | |||
+ | [[File:FirstQweakData_HV3400Volts_ChargeLeavingLastGEMFoil_4-04-09-Datafile_r877.gif]] |
Latest revision as of 19:07, 21 March 2011
A Min Ion Particle traversing Ar gas at 1 atm ionizes 22 atoms/cm Primary and 94-100 Total per cm. The Primary is an ionization from the incident particle, Total includes ionization from secondaries.
27 eV = average energy to ionize an electron in an Argon Atom
average number of photoelectrons produced
Quenching Gas:
1.) reduces the influence of the positive ions creates on the photoelectron signal: The excited Ar+ atoms emit photon in the UV range which are absorbed by the quenching gas
2.)Collisions with the quenching gas will neutralize the Ar+ ions. When the quenched gas, having an electron remove by the Ar+ collision, reaches the cathode and collects an electron, most of the energy goes into dissociation of the Quench gas.
If the quech gas is CH4 then
CH4+
H2 + CH2- Argon Escape peak
- You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits an X-ray which excapes the chamber.