Difference between revisions of "HRRL radiation tests"

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−
=Channel 17 Dose Estimation in New Position=
 
  
−
Channel 17 is a dose measuring detector on in the HRRL experimental cell.
+
=Calculation=
 +
 
 +
Assume that the position 13 at radiation test on Feb 4, 2009 by M. Balzer and G. Stancari will shift to detector position at corner on experiment that is done on 5/17/2010.
 +
 
 +
Radiation test on Feb 4, 2009 by M. Balzer and G. Stancari used OSL dosimeter.  
 +
 
 +
The area of a OSL dosimeter is:
  
−
== Calculating Number of Incident Electrons Per Second ==
+
<math>A_{osl} = 55.3536 \pm  3.0 ~mm^{2} </math>
  
−
We have electron beam of:
+
Experimental Cell Dose Measurement with HRRL on 5/17/2010 used [[Ludlums Gamma Area Monitor moedl 45-9]] for channel 16. [[Ludlums Gamma Area Monitor moedl 45-9]] has dimension: 7.6 x 25.7 cm (3 x 10.1 in.) (Dia x L).
  
−
Frequency:  f (Hz)
+
The area of a [[Ludlums Gamma Area Monitor moedl 45-9]] is:   
  
−
Peak current:  I (mAmp = 0.001 Amp)
+
<math> A_{lgam}=195.32 ~cm^{2} </math>
  
−
Pulse width: <math> \Delta</math> t ( <math> 1 ns=1*10^{-9} </math> seconds )
+
The ratio of detectors detecting area is:  
  
−
So, how many electrons we have in each second?
+
<math>\frac{ A_{osl} } {A_{lgam}} = 352.9 \pm 19 </math>
  
−
By Q=It, we have
+
We assume 100% efficiency for both detectors, their detecting are ratio is their dose ratio.
  
−
                                          <math>    N*e=f*I*\Delta t </math>
+
So, for 15 MeV electron beam, at the corner where we had detector of channel 16, if we moved detector to new position, on the detector of [[Ludlums Gamma Area Monitor moedl 45-9]] we would have dose rate of :
  
−
Where N is the total electron numbers hits target per second, e is electron charge and f, I and <math> \Delta t </math> are given above.
+
Dose <math> = (352.9 \pm 19) \times 5828 </math> (mrad/hr)
−
So
 
  
−
                          <math> N = f*I*\Delta t/e= f*I*\Delta t/(1.6*10^{-19}) </math>  
+
<math> = 2056701.2 \pm 110 732</math> (mrad/hr)
  
 +
<math> = 571.3 \pm 31 </math> (mrad/sec)
 +
                   
 +
Above dose is created by electron beam of energy 15 MeV and 20 mA peak current.
  
−
=== Number of Particles Per Second in test by M. Balzer on Feb 4, 2009 ===
 
  
−
In radiation levels measured on Feb 4, 2009 by M. Balzer and G. Stancari
 
  
−
Five OSL dosimeters were placed at each of 15 locations in the cell. (What is OSL? Need to ask M. Balzer)
+
According to the fit for Channel 16 at 16MeV, for 20 mA of peak current the dose should be:
  
−
The HRRL was set at 15 MeV beam energy, 20 mA peak current, 1 kHz repetition rate, and 30 ns pulse width.
+
<math> Dose = (-2.305 \pm 0.095) +  (0.511 \pm  0.01)*I_{peak} = (-2.305 \pm 0.095) +  (0.511 \pm  0.01)*20 = 1.96 \pm 0.27</math> (mrad/)
  
  
−
                              <math>  N = f*I*\Delta t/e= 1000*0.02*30*10^{-9}/(1.6*10^{-19}) =3.75*10^{12} </math>
+
According to the fit for Channel 17 at 10MeV, for 20 mA of peak current the dose should be:
  
 +
<math> (-0.039 \pm 0.066) +  (0.1001 \pm  0.01)*I_{peak} </math>
  
 +
The ratio,at 20 mA of peak current, of Channel 16 at 16MeV to Channel 17 at 10MeV is:
  
−
=== Number of Particles Per Second in "Experimental Cell Dose Measurement with HRRL" on 5/17/201  ===
+
<math> \frac{7.915 \pm 0.30}{1.96 \pm 0.27} = 4.03 \pm 0.57 </math>
  
  
−
This is the experiment we have done on 5/17/201 to measure dose on the detector placed in the corner of the doorway.
 
  
−
Conditions are: Pulse width: 1 <math>\mu  sec</math>, Rap rate: 110 Hz.
 
  
−
We measured dose for several peak current. One of the peak current is 26 mA. For this peak current:
 
  
  
−
                            <math>  N = f*I*\Delta t/e= 110*0.026*1*10^{-6}/(1.6*10^{-19}) = 1.7875*10^{13} </math>
 
  
−
=Calculation=
 
  
−
Assume that the position 13 at radiation test on Feb 4, 2009 by M. Balzer and G. Stancari will shift to detector position at corner on experiment that is done on 5/17/2010.
+
This dose is created by electron beam of energy 15 MeV and <math> 3.75 \times 10^{12} </math> electrons/second.
  
−
Radiation test on Feb 4, 2009 by M. Balzer and G. Stancari used OSL dosimeter.
+
So, per electron dose rate of 15 MeV beam is:
  
−
The area of a OSL dosimeter is:
 
  
−
<math>A_{osl} = 55.3536 \pm 3.0 ~mm^{2} </math>  
+
<math> \frac{571.3 \pm 31}{3.75 \times 10^{12}} = (1.523 \pm 0.083) \times 10^{-10} \frac{mrad}{sec*electron} </math>
  
−
Experimental Cell Dose Measurement with HRRL on 5/17/2010 used [[Ludlums Gamma Area Monitor moedl 45-9]] for channel 16. [[Ludlums Gamma Area Monitor moedl 45-9]] has dimension: 7.6 x 25.7 cm (3 x 10.1 in.) (Dia x L).
 
  
−
The area of a [[Ludlums Gamma Area Monitor moedl 45-9]] is: 
+
Also assume same dose rate for 16 MeV and 15 MeV electron beam energy.
  
−
<math> A_{lgam}=195.32 ~cm^{2} </math>
 
  
−
The ratio of detectors detecting area is:
 
  
−
<math>\frac{ A_{osl} } {A_{lgam}} = 352.9 \pm 19 </math>
+
=Channel 17 Dose Estimation in New Position=
  
−
We assume 100% efficiency for both detectors, their detecting are ratio is their dose ratio.  
+
Channel 17 is a dose measuring detector on in the HRRL experimental cell.
  
−
So, for 15 MeV electron beam, at the corner where we had detector of channel 16, if we moved detector to new position, on the detector of [[Ludlums Gamma Area Monitor moedl 45-9]] we would have dose rate of :
+
== Calculating Number of Incident Electrons Per Second ==
  
−
Dose <math> = (352.9 \pm 19) \times 5828 </math> (mrad/hr)
+
We have electron beam of:
  
−
<math> = 2056701.2 \pm 110 732</math> (mrad/hr)  
+
Frequency:  f (Hz)
  
−
<math> = 571.3 \pm 31 </math> (mrad/sec)
+
Peak current:  I (mAmp = 0.001 Amp)
−
                   
 
−
Above dose is created by electron beam of energy 15 MeV and 20 mA peak current.
 
  
 +
Pulse width: <math> \Delta</math> t ( <math> 1 ns=1*10^{-9} </math> seconds )
  
 +
So, how many electrons we have in each second?
  
−
According to the fit for Channel 16 at 16MeV, for 20 mA of peak current the dose should be:
+
By Q=It, we have
  
−
<math> Dose = (-2.305 \pm 0.095) +  (0.511 \pm  0.01)*I_{peak} = (-2.305 \pm 0.095) +  (0.511 \pm  0.01)*20 = 1.96 \pm 0.27</math> (mrad/)
+
                                          <math>   N*e=f*I*\Delta t </math>  
  
 +
Where N is the total electron numbers hits target per second, e is electron charge and f, I and <math> \Delta t </math> are given above.
 +
So
  
−
According to the fit for Channel 17 at 10MeV, for 20 mA of peak current the dose should be:
+
                          <math>  N = f*I*\Delta t/e= f*I*\Delta t/(1.6*10^{-19}) </math>
  
−
<math> (-0.039 \pm 0.066) +  (0.1001 \pm  0.01)*I_{peak} </math>
 
  
−
The ratio,at 20 mA of peak current, of Channel 16 at 16MeV to Channel 17 at 10MeV is:
+
=== Number of Particles Per Second in test by M. Balzer on Feb 4, 2009 ===
  
−
<math> \frac{7.915 \pm 0.30}{1.96 \pm 0.27} = 4.03 \pm 0.57 </math>
+
In radiation levels measured on Feb 4, 2009 by M. Balzer and G. Stancari
  
 +
Five OSL dosimeters were placed at each of 15 locations in the cell. (What is OSL? Need to ask M. Balzer)
  
 +
The HRRL was set at 15 MeV beam energy, 20 mA peak current, 1 kHz repetition rate, and 30 ns pulse width.
  
  
 +
                              <math>  N = f*I*\Delta t/e= 1000*0.02*30*10^{-9}/(1.6*10^{-19}) =3.75*10^{12} </math>
  
  
  
 +
=== Number of Particles Per Second in "Experimental Cell Dose Measurement with HRRL" on 5/17/201  ===
  
−
This dose is created by electron beam of energy 15 MeV and <math> 3.75 \times 10^{12} </math> electrons/second.
 
  
−
So, per electron dose rate of 15 MeV beam is:
+
This is the experiment we have done on 5/17/201 to measure dose on the detector placed in the corner of the doorway.
  
 +
Conditions are: Pulse width: 1 <math>\mu  sec</math>, Rap rate: 110 Hz.
  
−
<math> \frac{571.3 \pm 31}{3.75 \times 10^{12}} = (1.523 \pm 0.083) \times 10^{-10} \frac{mrad}{sec*electron}  </math>
+
We measured dose for several peak current. One of the peak current is 26 mA. For this peak current:
  
  
−
Also assume same dose rate for 16 MeV and 15 MeV electron beam energy.  
+
                            <math>  N = f*I*\Delta t/e= 110*0.026*1*10^{-6}/(1.6*10^{-19}) = 1.7875*10^{13} </math>
  
  

Revision as of 09:15, 31 May 2010

Building a new positron beamline in the HRRL cell might require moving the linac itself. R adiation levels were measured on Feb 4, 2009 by M. Balzer and G. Stancari to determine the impact of repositioning the HRRL RF cavity in the accelerator room.

The HRRL was used to accelerate electrons to a 15 MeV beam energy, 20 mA peak current, 1 kHz repetition rate, and 30 ns pulse width. Five OSL dosimeters (For Details on OSL dosimeter, look [[1]]) were placed at each of 15 locations within the cell identified in the sketch below.

Dosimeter-locations-20090204.png

Media:dosimeter-locations-20090204.pdf

Readings in mrad are reported in the following table. They were taken before exposure (first column) and after a couple of minutes of machine tuning (second column). Readings in the third column were taken 94 minutes after the second reading. During these 94 minutes, the machine was running with the settings mentioned above.

Exposure-measurements-20090204.png

Media:exposure-measurements-20090204.pdf

Dose rates in mrad/hr at each of the 15 locations can be estimated by subtracting column 2 from column 3, averaging over the 5 dosimeters, and multiplying the result by (60 min/hr) / (94 min). RMS spreads refer to variations within each group of 5.

Location Dose rate RMS spread
(mrad/hr) (mrad/hr)
1 9 4
2 396 57
3 7940 204
4 2831 117
5 4408 373
6 29339 3332
7 72517 687
8 36507 4746
9 5 5
10 37 4
11 164 40
12 2734 313
13 5828 120
14 7793 2579
15 62431 27155


OSL dosimeters

Dosimeters are placed approximately 1-m off the floor. Large face of the dosimeters were facing HRRL.

Diameter of a dosimeter is measured as:

d = 7.4 mm, 7.6 mm, 7.5 mm, 7.3 mm, 7.3 mm, 7.4 mm, 7.6 mm.

so,

d = 7.44 [math]\pm [/math] 0.13 mm.

OSL dosimeters.jpg

Experimental Cell Dose Measurement with HRRL

This experiment is done on 5/17/2010, at 10:00 am.


Experiment Setup.png


Dr. Khalid Chouffani wrote the note. Here is photocopy of his note:

page #1

Note P1.jpg

Note P1 2.jpg


page #2

Note P2.jpg


Detector Used on Channel 16

Channal 16 Detector 1.jpg

Channal 16 Detector 2.jpg

Channal 16 Detector 3.jpg

Link to detector information from producer: [2]

For more detailed information go to: ludlums_Gamma_Area_Monitor_moedl_45-9

16 MeV Beam Energy

Experimental cell measurement with HRRL.

Conditions are:

Rep rate: 40 Hz

Pulse width: 1 [math]\mu sec[/math]

[math]\Delta[/math]E=(10-17) MeV

Peak current of beam (mA) Energy of beam (MeV) Measurement on Channel 17, Experimental Cell (mrad) Measurement on Channel 16, Accelerator cell (mrad)
100 16 4.5 [math]\pm [/math] 0.2 45.5 [math]\pm [/math] 2
69.2 16 4 [math]\pm [/math] 0.2 35, 42.5
60.8 16 3.5 [math]\pm [/math] 0.1 29.2, 28.9
58.0 16 2.8, 2.9 26, 26.7
47.6 16 2.3 19.6, 21.3
33.2 16 1.8, 1.7 14.5, 14.0, 13.7

Beam bear through 1/4 inches diameter collimator with 4 inches lead.


16MeV Chan16.png


16MeV Chan17.png


Fit for Channel 16 at 16MeV

Order of the fit Fit equations Chi square p-value
1st order [math] Dose = (-2.305 \pm 0.095) + (0.511 \pm 0.01)*I_{peak} [/math] 22.38 0.00017

16 MeV Beam Energy

Conditions are:

Rep rate: 40 Hz

Peak current of beam (mA) Energy of beam (MeV) Measurement on Channel 17, Experimental Cell (mrad) Measurement on Channel 16, Accelerator cell (mrad)
136 16 0.3 99.2, 98.7

10 MeV Beam Energy

Conditions are:

Rep rate: 110 Hz

[math]\Delta[/math]E=(8-16) MeV

Peak current of beam (mA) Energy of beam (MeV) Measurement on Channel 17, Experimental Cell (mrad) Measurement on Channel 16, Accelerator cell (mrad)
48.4 10 4.6, 4.7 117.6, 117.5
36.8 10 3.8, 3.9 104.4, 103.5, 102.9
30.8 10 3.1 [math]\pm [/math] 0.1 72.8, 72.9, 72.5
26 10 2.5 56.7, 56.4, 54.6


10MeV Chan16.png


10MeV Chan17.png


Fit for channel 17 at 10 MeV

Order of the fit Fit equations Chi square p-value
1st order [math] Dose = (-0.039 \pm 0.066) + (0.1001 \pm 0.01)*I_{peak} [/math] 0.983 0.6117


Calculation

Assume that the position 13 at radiation test on Feb 4, 2009 by M. Balzer and G. Stancari will shift to detector position at corner on experiment that is done on 5/17/2010.

Radiation test on Feb 4, 2009 by M. Balzer and G. Stancari used OSL dosimeter.

The area of a OSL dosimeter is:

[math]A_{osl} = 55.3536 \pm 3.0 ~mm^{2} [/math]

Experimental Cell Dose Measurement with HRRL on 5/17/2010 used Ludlums Gamma Area Monitor moedl 45-9 for channel 16. Ludlums Gamma Area Monitor moedl 45-9 has dimension: 7.6 x 25.7 cm (3 x 10.1 in.) (Dia x L).

The area of a Ludlums Gamma Area Monitor moedl 45-9 is:

[math] A_{lgam}=195.32 ~cm^{2} [/math]

The ratio of detectors detecting area is:

[math]\frac{ A_{osl} } {A_{lgam}} = 352.9 \pm 19 [/math]

We assume 100% efficiency for both detectors, their detecting are ratio is their dose ratio.

So, for 15 MeV electron beam, at the corner where we had detector of channel 16, if we moved detector to new position, on the detector of Ludlums Gamma Area Monitor moedl 45-9 we would have dose rate of :

Dose [math] = (352.9 \pm 19) \times 5828 [/math] (mrad/hr)

[math] = 2056701.2 \pm 110 732[/math] (mrad/hr)

[math] = 571.3 \pm 31 [/math] (mrad/sec)

Above dose is created by electron beam of energy 15 MeV and 20 mA peak current.


According to the fit for Channel 16 at 16MeV, for 20 mA of peak current the dose should be:

[math] Dose = (-2.305 \pm 0.095) + (0.511 \pm 0.01)*I_{peak} = (-2.305 \pm 0.095) + (0.511 \pm 0.01)*20 = 1.96 \pm 0.27[/math] (mrad/)


According to the fit for Channel 17 at 10MeV, for 20 mA of peak current the dose should be:

[math] (-0.039 \pm 0.066) + (0.1001 \pm 0.01)*I_{peak} [/math]

The ratio,at 20 mA of peak current, of Channel 16 at 16MeV to Channel 17 at 10MeV is:

[math] \frac{7.915 \pm 0.30}{1.96 \pm 0.27} = 4.03 \pm 0.57 [/math]





This dose is created by electron beam of energy 15 MeV and [math] 3.75 \times 10^{12} [/math] electrons/second.

So, per electron dose rate of 15 MeV beam is:


[math] \frac{571.3 \pm 31}{3.75 \times 10^{12}} = (1.523 \pm 0.083) \times 10^{-10} \frac{mrad}{sec*electron} [/math]


Also assume same dose rate for 16 MeV and 15 MeV electron beam energy.


Channel 17 Dose Estimation in New Position

Channel 17 is a dose measuring detector on in the HRRL experimental cell.

Calculating Number of Incident Electrons Per Second

We have electron beam of:

Frequency: f (Hz)

Peak current: I (mAmp = 0.001 Amp)

Pulse width: [math] \Delta[/math] t ( [math] 1 ns=1*10^{-9} [/math] seconds )

So, how many electrons we have in each second?

By Q=It, we have 

                                         [math]    N*e=f*I*\Delta t [/math]

Where N is the total electron numbers hits target per second, e is electron charge and f, I and [math] \Delta t [/math] are given above. So 

                          [math]  N = f*I*\Delta t/e= f*I*\Delta t/(1.6*10^{-19}) [/math]


Number of Particles Per Second in test by M. Balzer on Feb 4, 2009

In radiation levels measured on Feb 4, 2009 by M. Balzer and G. Stancari

Five OSL dosimeters were placed at each of 15 locations in the cell. (What is OSL? Need to ask M. Balzer)

The HRRL was set at 15 MeV beam energy, 20 mA peak current, 1 kHz repetition rate, and 30 ns pulse width. 


                             [math]  N = f*I*\Delta t/e= 1000*0.02*30*10^{-9}/(1.6*10^{-19}) =3.75*10^{12} [/math]


Number of Particles Per Second in "Experimental Cell Dose Measurement with HRRL" on 5/17/201

This is the experiment we have done on 5/17/201 to measure dose on the detector placed in the corner of the doorway.

Conditions are: Pulse width: 1 [math]\mu sec[/math], Rap rate: 110 Hz.

We measured dose for several peak current. One of the peak current is 26 mA. For this peak current: 


                           [math]  N = f*I*\Delta t/e= 110*0.026*1*10^{-6}/(1.6*10^{-19}) = 1.7875*10^{13} [/math]



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