Difference between revisions of "Theoretical analysis of 2n accidentals rates"

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[[Production Analysis | go_back]]
 
[[Production Analysis | go_back]]
 
==Introduction==
 
==Introduction==
A given photon pulse may cause multiple neutron-producing reactions, ranging from zero to "infinity" reactions. The number of neutron-producing reactions in a pulse is hereafter denoted by <math>n</math>. Being the number of neutron-producing reactions ''actually'' occurring per pulse, <math>n</math> is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces <math>v_{i}</math> neutrons, where <math>v_{i}</math> is the distribution of the number of neutrons produced from an individual neutron-producing reaction. The beam has a Bremsstrahlung end point of 10.5 MeV, energetically allowing two possible neutron-producing interactions, 1n-knochout and photofission, so <math>v_{i}</math> is simply the photofission neutron multiplicity with an added contribution from 1n-knockout events. In other words, a 1n-knockout event and a photo-fission event emitting exactly one neutron, are considered identically. In viewing it this way, the analysis is simplified, but the end result is not changed since 1n-knockouts can only contribute to accidentals.
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A given photon pulse may cause multiple neutron-producing reactions, ranging from zero to "infinity" reactions. The number of neutron-producing reactions in a pulse is hereafter denoted by <math>n</math>. Being the number of neutron-producing reactions ''actually'' occurring per pulse, <math>n</math> is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces <math>v_{i}</math> neutrons, where <math>v_{i}</math> is the distribution of the number of neutrons produced from an individual neutron-producing reaction. The beam has a Bremsstrahlung end point of 10.5 MeV, energetically allowing only two possible neutron-producing interactions, 1n-knochout and photofission. Thus, <math>v_{i}</math> is the photofission neutron multiplicity, plus a component of <math>v_{i}=1</math> from 1n-knockout events. In other words, a 1n-knockout event and a photo-fission event emitting exactly one neutron, are considered identically. In viewing it this way, the analysis is simplified, but the end result is not changed since 1n-knockouts can only contribute to accidentals.

Revision as of 18:13, 9 January 2018

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Introduction

A given photon pulse may cause multiple neutron-producing reactions, ranging from zero to "infinity" reactions. The number of neutron-producing reactions in a pulse is hereafter denoted by [math]n[/math]. Being the number of neutron-producing reactions actually occurring per pulse, [math]n[/math] is assumed to follow the Poissonian distribution as a limiting case of the binomial distribution. Each neutron-producing interaction produces [math]v_{i}[/math] neutrons, where [math]v_{i}[/math] is the distribution of the number of neutrons produced from an individual neutron-producing reaction. The beam has a Bremsstrahlung end point of 10.5 MeV, energetically allowing only two possible neutron-producing interactions, 1n-knochout and photofission. Thus, [math]v_{i}[/math] is the photofission neutron multiplicity, plus a component of [math]v_{i}=1[/math] from 1n-knockout events. In other words, a 1n-knockout event and a photo-fission event emitting exactly one neutron, are considered identically. In viewing it this way, the analysis is simplified, but the end result is not changed since 1n-knockouts can only contribute to accidentals.