Difference between revisions of "User talk:Brian"

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<ref>Phoenix: The Peoples of the Hills: Ancient Ararat and Caucasus by Charles Burney , David Marshall Lang, Phoenix Press; New Ed edition (December 31, 2001)</ref>
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http://brems.iac.isu.edu/mrtg/cleantemp1-day.png <br/>
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<!-- http://134.50.3.81/image.png -->
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===Odds===
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Finally, <math>\{u_1, u_2, u_3\} = \{ 1, 2\sqrt{3}(t-1/2), 6\sqrt{5}(t^2-t+1/6) \}</math>.
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(b) Let <math>B = \{u_1,u_2,u_3\}</math> be the orthonormal basis found above.
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For any <math>f(t) = at^2+bt+c \in U</math>
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<br/>
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<math> f(t) = \sum_{i=1}^3 a_iu_i(t)
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= \left( \frac{a}{3}+\frac{b}{2}+c \right) + \left( \frac{\sqrt{3}}{3}(a+b) \right) 2\sqrt{3} \left( t-\frac{1}{2} \right)
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  + \left( \frac{\sqrt{5}}{30}a \right) 6\sqrt{5} \left( t^2-t+\frac{1}{6} \right)
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</math>
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<br/>
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<math>
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= \frac{a}{3}+\frac{b}{2}+c
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  - a - b + 2at + 2bt 
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  + at^2 - at + \frac{a}{6}
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</math>
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<br/>
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<math>
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= at^2 + t (a+2b) -\frac{1}{2}(a+b-2c)
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</math>
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<math>\sqrt{1-e^2}</math>
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[[Gumstix Crapola]]
  
http://www.iac.isu.edu/mediawiki/index.php?title=Special:Userlogin&type=signup
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[[Origin licensing]]
  
Also known as:
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[[Image:Brian_test.png | 10px]]
  
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Go to this page to add new users:
 
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[[Special:Userlogin]]
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And this page to modify groups:
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[[Special:UserRights]]
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[[Micro_Cluster]]<br/>
  
  
*Clusters
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[[Brian Articles]]
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Latest revision as of 23:05, 26 May 2010

<ref>Phoenix: The Peoples of the Hills: Ancient Ararat and Caucasus by Charles Burney , David Marshall Lang, Phoenix Press; New Ed edition (December 31, 2001)</ref>

http://brems.iac.isu.edu/mrtg/cleantemp1-day.png


Odds

Finally, [math]\{u_1, u_2, u_3\} = \{ 1, 2\sqrt{3}(t-1/2), 6\sqrt{5}(t^2-t+1/6) \}[/math].

(b) Let [math]B = \{u_1,u_2,u_3\}[/math] be the orthonormal basis found above. For any [math]f(t) = at^2+bt+c \in U[/math]
[math] f(t) = \sum_{i=1}^3 a_iu_i(t) = \left( \frac{a}{3}+\frac{b}{2}+c \right) + \left( \frac{\sqrt{3}}{3}(a+b) \right) 2\sqrt{3} \left( t-\frac{1}{2} \right) + \left( \frac{\sqrt{5}}{30}a \right) 6\sqrt{5} \left( t^2-t+\frac{1}{6} \right) [/math]
[math] = \frac{a}{3}+\frac{b}{2}+c - a - b + 2at + 2bt + at^2 - at + \frac{a}{6} [/math]
[math] = at^2 + t (a+2b) -\frac{1}{2}(a+b-2c) [/math]


[math]\sqrt{1-e^2}[/math]

Gumstix Crapola

Origin licensing

Brian test.png

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