Difference between revisions of "User talk:Brian"

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<br/>
 
<br/>
 
<math>
 
<math>
  = at^2 +  
+
  = at^2 + t (a+2b) -\frac{1}{2}(a+b-2c)
 
</math>
 
</math>
  

Revision as of 18:17, 12 March 2010

<ref>Phoenix: The Peoples of the Hills: Ancient Ararat and Caucasus by Charles Burney , David Marshall Lang, Phoenix Press; New Ed edition (December 31, 2001)</ref>

http://brems.iac.isu.edu/mrtg/cleantemp1-day.png


Odds

Finally, [math]\{u_1, u_2, u_3\} = \{ 1, 2\sqrt{3}(t-1/2), 6\sqrt{5}(t^2-t+1/6) \}[/math].

(b) Let [math]B = \{u_1,u_2,u_3\}[/math] be the orthonormal basis found above. For any [math]f(t) = at^2+bt+c \in U[/math]
[math] f(t) = \sum_{i=1}^3 a_iu_i(t) = \left( \frac{a}{3}+\frac{b}{2}+c \right) + \left( \frac{\sqrt{3}}{3}(a+b) \right) 2\sqrt{3} \left( t-\frac{1}{2} \right) + \left( \frac{\sqrt{5}}{30}a \right) 6\sqrt{5} \left( t^2-t+\frac{1}{6} \right) [/math]
[math] = \frac{a}{3}+\frac{b}{2}+c - a - b + 2at + 2bt + at^2 - at + \frac{a}{6} [/math]
[math] = at^2 + t (a+2b) -\frac{1}{2}(a+b-2c) [/math]


[math]\sqrt{1-e^2}[/math]

Gumstix Crapola

Origin licensing

Brian test.png

Go to this page to add new users: Special:Userlogin

And this page to modify groups: Special:UserRights

Micro_Cluster

MCNPX MPI Windows

  • Copy MCNPX directory
  • Install MPICH2
  • Set datapath, add mpich2 to path
  • Restrict firewall permissions to 127.0.0.1
  • MPICH2 password should be blank
  • mpiexec -np 3 mcnpx i=...