Difference between revisions of "TF EIMLab3 Writeup"

From New IAC Wiki
Jump to navigation Jump to search
Line 2: Line 2:
  
 
= 1-50 kHz filter (20 pnts)=
 
= 1-50 kHz filter (20 pnts)=
# Design a low-pass RC filter with a break point between 1-50 kHz.  The break point is the frequency at which the filter starts to attenuate the AC signal.  For a Low pass filter, AC signals with a frequency above 1-50 kHz will start to be attenuated (not passed).
+
#Design a low-pass RC filter with a break point between 1-50 kHz.  The break point is the frequency at which the filter starts to attenuate the AC signal.  For a Low pass filter, AC signals with a frequency above 1-50 kHz will start to be attenuated (not passed).
 
#Now construct the circuit using a non-polar capacitor.
 
#Now construct the circuit using a non-polar capacitor.
 
#use a sinusoidal variable frequency oscillator to provide an input voltage to your filter.
 
#use a sinusoidal variable frequency oscillator to provide an input voltage to your filter.
Line 16: Line 16:
 
|  || || ||
 
|  || || ||
 
|-
 
|-
|  || || ||
+
| 50 || 0.6|| 0.3||
 +
|-
 +
| 100 || 0.5|| 0.18||
 +
|-
 +
| 250 || 0.5|| 0.075||
 +
|-
 +
| 500 || 0.45|| 0.04||
 +
|-
 +
|1000 ||0.4 ||0.017 ||
 
|-
 
|-
| || || ||
+
| 2500 || 0.28|| 0.005 ||
 
|-
 
|-
| || || ||
+
| 5056 || 0.16|| 0.005||
 
|-
 
|-
 
|  || || ||
 
|  || || ||

Revision as of 03:35, 21 January 2011

RC Low-pass filter

1-50 kHz filter (20 pnts)

  1. Design a low-pass RC filter with a break point between 1-50 kHz. The break point is the frequency at which the filter starts to attenuate the AC signal. For a Low pass filter, AC signals with a frequency above 1-50 kHz will start to be attenuated (not passed).
  2. Now construct the circuit using a non-polar capacitor.
  3. use a sinusoidal variable frequency oscillator to provide an input voltage to your filter.
  4. Measure the input [math](V_{in})[/math] and output [math](V_{out})[/math] voltages for at least 8 different frequencies[math] (\nu)[/math] which span the frequency range from 1 Hz to 1 MHz.
[math]\nu[/math] [math]V_{in}[/math] [math]V_{out}[/math] [math]\frac{V_{out}}{V_{in}}[/math]
Hz Volts Volts
50 0.6 0.3
100 0.5 0.18
250 0.5 0.075
500 0.45 0.04
1000 0.4 0.017
2500 0.28 0.005
5056 0.16 0.005
  1. Graph the [math]\log \left(\frac{V_{out}}{V_{in}} \right)[/math] -vs- [math]\log (\nu)[/math]


TF EIM Lab3.png

phase shift (10 pnts)

  1. measure the phase shift between [math]V_{in}[/math] and [math]V_{out}[/math]

Questions

  1. compare the theoretical and experimentally measured break frequencies. (5 pnts)
  2. Calculate and expression for [math]\frac{V_{out}}{ V_{in}}[/math] as a function of [math]\nu[/math], [math]R[/math], and [math]C[/math]. The Gain is defined as the ratio of [math]V_{out}[/math] to [math]V_{in}[/math].(5 pnts)
  3. Compare the theoretical and experimental value for the phase shift [math]\theta[/math]. (5 pnts)
  4. Sketch the phasor diagram for [math]V_{in}[/math],[math] V_{out}[/math], [math]V_{R}[/math], and [math]V_{C}[/math]. Put the current [math]i[/math] along the real voltage axis. (30 pnts)
  5. what is the phase shift [math]\theta[/math] for a DC input and a very-high frequency input?(5 pnts)
  6. calculate and expression for the phase shift [math]\theta[/math] as a function of [math]\nu[/math], [math]R[/math], [math]C[/math] and graph [math]\theta[/math] -vs [math]\nu[/math]. (20 pnts)


Forest_Electronic_Instrumentation_and_Measurement