Difference between revisions of "Spontaneous fission rate for sample of U-235 (1mg/cm^2)"
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Goal: Calculate the fission rate of a bomb grade U235 that has a mass of .91*10^-3 g. | Goal: Calculate the fission rate of a bomb grade U235 that has a mass of .91*10^-3 g. | ||
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Procedure: | Procedure: | ||
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| − | + | Given - | |
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| + | T1/2 = 7.038 * 10^8 year =>7.038 * 10^8 year * 3153600 seconds/year = 2.2195 * 10^16 sec | ||
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| + | m = .91 * 10^-3 g | ||
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| + | Calculations - | ||
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| + | No = (Na/A) * m = ([6.022 * 10^23 nuclei/mol] / [235 g/mol])* (.91 * 10^-3 g) = 2.33 * 10^18 nuclei | ||
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| + | λ = ln(2)/T1/2 =ln(2)/(2.2195 *10^16 sec) = 3.12 * 10^-17 sec-1 | ||
Revision as of 23:12, 23 April 2008
Goal: Calculate the fission rate of a bomb grade U235 that has a mass of .91*10^-3 g.
Procedure:
Given -
T1/2 = 7.038 * 10^8 year =>7.038 * 10^8 year * 3153600 seconds/year = 2.2195 * 10^16 sec
m = .91 * 10^-3 g
Calculations -
No = (Na/A) * m = ([6.022 * 10^23 nuclei/mol] / [235 g/mol])* (.91 * 10^-3 g) = 2.33 * 10^18 nuclei
λ = ln(2)/T1/2 =ln(2)/(2.2195 *10^16 sec) = 3.12 * 10^-17 sec-1