Se170063 Nickel Foil Thin Gauss Window Expansion

This analysis was done by weighting the histogram by the mass of the sample. The window is [1360,1365] and was expanded by one channel on each side to find the error in the counts.

	5/25/17	5/26/17	5/27/17	5/29/17	5/30/17	5/31/17	6/1/17
Original Window Counts	92120	157200
Original Window Background (Integrated)	12773.2	58525.7
Original Window Difference	79346.8	98674.3
Expanded Window Counts	95730
Expanded Window Background	921.179
Expanded Window Difference	94808.821
Error in counts	15462.021
Position	50 cm	30 cm	20cm	20 cm	10cm	10cm	10cm
Efficiency	0.00017	0.000422	0.000847	0.000847	0.0031	0.0031	0.0031
.dat file entry	14.25306628 +/- 0.1948663462

Below is a plot of the activity as a function of time

This gives the constant of 14.5046 +/- 0.00345043. Now find the initial activity

[math] A_t = e^{14.5046} = 1991900.96 Hz [/math]

Since the plot is made with reference to the mixture's measurement time (first point plotted 108 minutes after the mix was measured) means that the constant should be the activity at the time the mixture was being measured.