Difference between revisions of "Relativistic Frames of Reference"

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<center>'''<u>Galilean Transformations</u>\ \ \ <u>LorentzTransformations</u>'''</center>
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<center>{{colbegin}}'''<u>Galilean Transformations</u><u>LorentzTransformations</u>'''{{colend}}</center>
 
<center><math>\begin{cases}
 
<center><math>\begin{cases}
 
t= t' \\
 
t= t' \\

Revision as of 03:26, 4 June 2017

[math]\textbf{\underline{Navigation}}[/math]

[math]\vartriangleleft [/math] [math]\triangle [/math] [math]\vartriangleright [/math]

Relativistic Frames of Reference

From the Galilean description of motion for a frame of reference moving relative to another frame considered stationary we know that


Galilean Frames of Reference
Figure 2.1: Primed reference frame moving in the z direction with velocity v.


[math]\begin{cases} t= t' \\ x=x' \\ y=y' \\ z=z'+vt \end{cases}[/math]


Using Einstein's Theory of Relativity, we know that the speed of light is a constant, c, for all reference frames. In the unprimed frame, from the definition of speed:


[math]speed=\frac{\Delta Distance}{\Delta Time}[/math]


[math]c=\frac{\Delta d}{\Delta t}[/math]


where

[math]c=3\times 10^8\ m/s[/math]

Using the distance equation in a Cartesian coordinate system, the equation for the speed of light becomes


[math]c=\frac{\sqrt{\Delta x^2+\Delta y^2+\Delta z^2}}{t}[/math]


Following the postulate of Special Relativity, this implies for the primed frame


[math]c=\frac{\sqrt{\Delta x^{'2}+\Delta y^{'2}+\Delta z^{'2}}}{t}[/math]



We can rewrite this as


[math]\frac{\Delta x^{'2}+\Delta y^{'2}+\Delta z^{'2}}{\Delta t^{'2}}= c^2=\frac{\Delta x^2+\Delta y^2+\Delta z^2}{\Delta t^2}[/math]


This is possible since the ratios of distance to time are multiples of the same base, i.e. the square of the speed of light [math](\frac{3\times 10^8\ m}{s})^2[/math]. Therefore for the relative change in the time in one frame, the distance must change by the same factor to maintain the same constant. With this we can write


[math]c^2 \Delta t^{'2}=\Delta x^{'2}+\Delta y^{'2}+\Delta z^{'2}\ \ \ \ \ c^2 \Delta t^{2}=\Delta x^2+\Delta y^2+\Delta z^2[/math]



[math]\Rightarrow c^2 \Delta t^{'2}-\Delta x^{'2}-\Delta y^{'2}-\Delta z^{'2}= c^2 \Delta t^{2}-\Delta x^2-\Delta y^2-\Delta z^2[/math]


This quantity is known as the time space interval [math]ds^2[/math] when the change is infinitesimal


[math]s^2\equiv c^2 dt^{'2}-dx^{'2}-dy^{'2}-dz^{'2}= c^2 dt^{2}-dx^2-dy^2-dz^2[/math]


Since the speed of light is a constant for all frames of reference, this allows the space time interval to also be invariant for inertial frames.

[math]s^2\equiv c^2 dt^{'2}-dx^{'2}-dy^{'2}-dz^{'2}= c^2 dt^{2}-dx^2-dy^2-dz^2[/math]


[math]s^2\equiv c^2 dt^{'2}-dr^{'2}= c^2 dt^{2}-dr^2[/math]


[math]s^2\equiv (c^2 -v^{'2})dt^{'2}= (c^2 -v^2)dt^{2}[/math]


From the rest frame of v'=0


[math]s^2\equiv c^2 dt^{'2}= (c^2 -v^2)dt^{2}[/math]


[math]\Rightarrow dt^{'2}= (1-\frac{v^2}{c^2 })dt^{2}[/math]


[math]\Rightarrow \begin{cases} dt'= \sqrt{1-\frac{v^2}{c^2 }}dt=\frac{1}{\gamma} dt\\ \\ dt= \frac{1}{\sqrt{1-\frac{v^2}{c^2 }}}dt'=\gamma dt' \end{cases}[/math]


Assuming motion is only along the z direction


[math]v \equiv \frac{dz}{dt}[/math]


[math]dz=v\ d t=v \frac{1}{\sqrt{1-\frac{v^2}{c^2 }}}dt'=\gamma v dt'[/math]


[math]z=\gamma v t'[/math]


Substituting these changes into the Galilean transformations


Template:ColbeginGalilean TransformationsLorentzTransformationsTemplate:Colend
[math]\begin{cases} t= t' \\ x=x' \\ y=y' \\ z=z'+vt \end{cases}\ \ \Rightarrow \ \ \begin{cases} t= t' \\ x=x' \\ y=y' \\ z=z'+vt \end{cases}[/math]


[math]\textbf{\underline{Navigation}}[/math]

[math]\vartriangleleft [/math] [math]\triangle [/math] [math]\vartriangleright [/math]