Difference between revisions of "Radius of Curvature Calculation"

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<math>r = \frac{\rho}{q*B}</math>
 
<math>r = \frac{\rho}{q*B}</math>
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For this sample equation 1 MeV will be used to determine the radius of curvature per MeV of the incident beam.
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Energy = 1 MeV
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Magnetic Field (B) = 0.35 Tesla
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Charge of an electron = <math>1.6022 * 10^{19} C</math>

Revision as of 08:31, 17 February 2009

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Below are my calculations done for determining the radius of curvature of an electron/positron in the magnetic field for the pair spectrometer.

The Lorentz force is the centripetal force acting upon the electron/positron in the magnetic field which gives the following equation.

[math]\frac{(m*v^2)}{r} = q * v * B [/math]

This equation can be rearranged to solve for r (and given that mv = momentum) to give the following equation

[math]r = \frac{\rho}{q*B}[/math]

For this sample equation 1 MeV will be used to determine the radius of curvature per MeV of the incident beam.

Energy = 1 MeV

Magnetic Field (B) = 0.35 Tesla

Charge of an electron = [math]1.6022 * 10^{19} C[/math]