# Difference between revisions of "Plastic Scintillator Calculation"

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I checked out a few of the physics material supply sites and most of them list with their products the amounts of each individual atom per <math> cm^3</math>. Therefore there is a quicker way to calculate the probability of interaction which is listed below. | I checked out a few of the physics material supply sites and most of them list with their products the amounts of each individual atom per <math> cm^3</math>. Therefore there is a quicker way to calculate the probability of interaction which is listed below. | ||

− | Probability of interaction <math>= \frac{NumCarbonAtoms}{cm^3}</math> | + | Probability of interaction <math>= (\frac{NumCarbonAtoms}{cm^3} * MF#H(\sigma_{elec}C + \sigma_{nucleus}C)) + (\frac{NumCarbonAtoms}{cm^3}*MF#H(\sigma_{elec}H + \sigma_{nucleus}H</math> |

[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] | [http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] |

## Revision as of 05:50, 5 February 2009

Below is the calculations done to determine the probability of pair production depending on thickness of the scintillator.

Molecules per

(NOTE: is just the density of the scintillator material and N[A] is Avogadro's number)Molecules per

Weighted cross-section

Probability of interaction (%)

All cross sections listed here are pair production cross-sections

For carbon

orFor carbon

orFor hydrogen

orFor hydrogen

orAvogadro's number

Molecular formula for PVT

Density of polyvinyl toluene (a common scintillator material) [1])

(NOTE: this value is from Rexon RP 200or is it [2] (TF)H/C = 11/10

For the sample calculation the thickness will be set to 1 cm just to get probability per cm

So entering all the numbers into the 4 initial equations gives the following answers:

Molecules per

Molecules per

Weighted cross-section

Probability of interaction (%)

Doing the same calculations using the Bicron BC 408 PVT with anthracene [3] for the material yields a probability of

# A different way to calculate probability of interaction

I checked out a few of the physics material supply sites and most of them list with their products the amounts of each individual atom per

. Therefore there is a quicker way to calculate the probability of interaction which is listed below.Probability of interaction