Difference between revisions of "Plastic Scintillator Calculation"

From New IAC Wiki
Jump to navigation Jump to search
Line 3: Line 3:
 
Molecules per <math> cm^3 = \frac{grams CH_{2}}{cm^3} * \frac{mol}{gram} * \frac{N[A]}{mol} </math>
 
Molecules per <math> cm^3 = \frac{grams CH_{2}}{cm^3} * \frac{mol}{gram} * \frac{N[A]}{mol} </math>
  
Molecules per <math> cm^2 = Molecules per cm^3 * Thickness </math>
+
Molecules per <math> cm^2 = \frac{Molecules}{cm^3} * Thickness </math>
  
  

Revision as of 23:44, 4 February 2009

Below is the calculations done to determine the probability of pair production depending on thickness of the scintillator.

Molecules per [math] cm^3 = \frac{grams CH_{2}}{cm^3} * \frac{mol}{gram} * \frac{N[A]}{mol} [/math]

Molecules per [math] cm^2 = \frac{Molecules}{cm^3} * Thickness [/math]


Weighted cross-section [math]= (\sigma_{elec}C + \sigma_{nucleus}C) + 2(\sigma_{elec}H + \sigma_{nucleus}H)[/math]

Go Back