Difference between revisions of "Monte Carlo Binary Collision Approximation"

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Nuclear fission of uranium-235 yields an enormous amount of energy from the fact that the fission products have less total mass than the uranium nucleus, a mass change that is converted to energy by the Einstein relationship <math>E=mc^2</math>.  Using the Law of Conservation of Energy, we can look at the total energy before and after the fission to determine how much energy is released in this process.
 
Nuclear fission of uranium-235 yields an enormous amount of energy from the fact that the fission products have less total mass than the uranium nucleus, a mass change that is converted to energy by the Einstein relationship <math>E=mc^2</math>.  Using the Law of Conservation of Energy, we can look at the total energy before and after the fission to determine how much energy is released in this process.
  
<center><math>^{235}_{92}U  : 92(938.272\ MeV)+143(939.565\ MeV)\ =\ \ GeV</math></center>
+
<center><math>^{236}_{92}U  : 92(938.272\ MeV)+144(939.565\ MeV)\ =\ 221.618\ GeV</math></center>
<center><math>^{140}_{54}Xe : 54(938.272\ MeV)+86(939.565\ MeV)\ =\ \ GeV</math></center>
+
<center><math>^{140}_{54}Xe : 54(938.272\ MeV)+86(939.565\ MeV)\ =\ 131.469\ GeV</math></center>
<center><math>^{94}_{38}Sr  : 38(938.272\ MeV)+56(939.565\ MeV)\ =\ \ GeV</math></center>
+
<center><math>^{94}_{38}Sr  : 38(938.272\ MeV)+56(939.565\ MeV)\ =\ 88.269\ GeV</math></center>
<center><math>2*n : 2(939.565\ MeV)\ =\ 1.879\ GeV</center>
+
<center><math>2*n : 2(939.565\ MeV)\ =\ 1.879\ GeV</math></center>
 
<center><math>-----------------------------</math></center>
 
<center><math>-----------------------------</math></center>
 
<center><math> Energy released=
 
<center><math> Energy released=

Revision as of 03:45, 26 February 2019

When uranium-235 undergoes fission, the average of the fragment mass is about 118, but it is more probable that the pair will have an unequal distribution in mass. A common pair of fragments from uranium-235 fission is xenon and strontium as shown in the reaction:


[math]^{235}U+n\rightarrow ^{236}U^{*} \rightarrow ^{140}Xe+^{94}Sr+2n[/math]


Figure 1: Typical Uranium 235 fission fragments Xenon and Strontium.


Nuclear fission of uranium-235 yields an enormous amount of energy from the fact that the fission products have less total mass than the uranium nucleus, a mass change that is converted to energy by the Einstein relationship [math]E=mc^2[/math]. Using the Law of Conservation of Energy, we can look at the total energy before and after the fission to determine how much energy is released in this process.

[math]^{236}_{92}U : 92(938.272\ MeV)+144(939.565\ MeV)\ =\ 221.618\ GeV[/math]
[math]^{140}_{54}Xe : 54(938.272\ MeV)+86(939.565\ MeV)\ =\ 131.469\ GeV[/math]
[math]^{94}_{38}Sr : 38(938.272\ MeV)+56(939.565\ MeV)\ =\ 88.269\ GeV[/math]
[math]2*n : 2(939.565\ MeV)\ =\ 1.879\ GeV[/math]
[math]-----------------------------[/math]
<math> Energy released=