Linac Run Plan April 2018, Dr. McNulty

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Beam Line info

Machine: 25b Linac

0[math]°[/math] port

Beam Energy: 8 MeV

Rep Rate: Max (150Hz?)

Pulse Width: 100ns

Run Plan

To find operating point

- Will use 15 OSLs from reproducibility study to make sure that dose is within acceptable range

Table

Start at 7am

Shot # Number of Pulses Number of OSLs Beam Current Dose/pulse Expected Dose/pulse
1 80 1 50 mA
2 1 mA
3 1 mA
4 1 mA
5 1 mA
6 1 mA
7 1 mA
8 1 mA
9 1 mA
10 1 mA
11 1 mA
12 1 mA
13 1 mA
14 1 mA
15 1 mA

Experiment

85 Nanodot OSLs for use (dose not include OSLs from reproducibility study)

- upper limit of OSLs is 15Gy, want to be around 7.5Gy with multiple pulses

Will talk to engineers about double pulsing and guaranteeing number of pulses and update.

Table

Shot # Number of Pulses Number of OSLs Beam Current Aluminum Brick Dose/Pulse Expected Dose/Pulse
1 1 mA Out
2 1 mA Out
3 1 mA Out
4 1 mA Out
5 1 mA Out
6 1 mA Out
7 16 mA In
8 16 mA In
9 16 mA Out
10 16 mA Out
11 16 mA Out

Absorbed Dose Information

Titanium window = 0.5mm thick. Radius = 23.813mm

Air gap between Titanium window and glass slide = 45mm

Glass slide Thickness = 1mm

5mA, 100ns pulse width, 100cm from beam pipe with Titanium window

25mA, 100ns pulse width, 100cm from beam pipe, with Titanium window

10mA, 100ns pulse width, 100cm from beam pipe, with Titanium window

100mA, 100ns pulse width, 100cm from beam pipe, with Titanium window

25mA, 100ns pulse width, 50cm from beam pipe, tungsten target with aluminum beamstop


100mA, 100ns pulse width, 25cm from beam pipe

25mA, 100ns pulse width, 25cm from beam pipe

25mA, 100ns pulse width, 50cm from beam pipe


Low Dose Line: Dose = (0.11 +/- 0.01)(PMT Counts) + (119.29 +/- 29.08)

High Dose Line: Dose = (1.54 +/- 0.06)(PMT Counts) + (1004.80 +/- 1006.24)


Peak Current: [math]50\frac{mA}{pulse}[/math]

Pulse Width: [math]500ns[/math]


[math]50\frac{mA}{pulse}=50\frac{mC}{s*pulse}=0.050\frac{C}{s*pulse}[/math]

[math]0.050\frac{C}{s*pulse}(500ns)=2.5*10^{-8}\frac{C}{pulse}[/math]

[math]2.5*10^{-8}\frac{C}{pulse}*\frac{1\ e-}{1.602*10^{-19}}=1.56055*10^{11}\frac{e-}{pulse}[/math]




Thesis

May 31st 2018 - 25b 0 degree port