# Difference between revisions of "Lab 9 RS"

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4) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time using your scope observations. (20 pnts) | 4) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time using your scope observations. (20 pnts) | ||

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6) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes) (20 pnts) | 6) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes) (20 pnts) | ||

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=Questions= | =Questions= |

## Revision as of 23:04, 24 February 2011

**Lab 9: Diode Circuits**

# Clipping Circuit

1.) Construct the circuit shown below using a silicon diode.

I am going to use:

```
1) Zener diode 4.7 V 1N5230B-T
2) the resistor
```

2.) Use a sine wave generator to drive the circuit so

where V and = 1kHz. (20 pnts)3.) Based on your observations using a oscilloscope, sketch the voltages

and as a function of time.4.) Do another sketch for

= 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)

For the last sketch the output voltage is . Let's estimate the power dissipated in resistor and diode. The current can be calculated by .

`The resistor power is given by `

. So we are OK here.
`The diode power is given by `

. So we are OK here as well. No any smoke out.
# Differentiating Circuit with clipping

1) Construct the circuit below.

2) Select and such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at is 3 V when there is no input pulse.

Because we want to keep the current below and using . Solving this inequality we get the first condition for and

` `

Also because we want and using . Without any input pulse . Solving this simple equation we get the second condition for and

` `

I am going to useand which satisfy both conditions above

3) Select a capacitor and a pulse width to form a differentiating circuit for the pulse from the signal generator. Hint: .

Taking and .

And choosing the the pulse width

I will be able to make a good differentiator circuit.

4) plot

and as a function of time using your scope observations. (20 pnts)

5) Now add the diode circuit from part 1 to prevent from rising above +5 V. Sketch the new circuit below.

6) plot and as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes) (20 pnts)

# Questions

- Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)

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