Difference between revisions of "Lab 9 RS"

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[[File:TF_EIM_Lab9a.png | 400 px]]
 
[[File:TF_EIM_Lab9a.png | 400 px]]
 
#Select <math>R_1</math> and <math>R_2</math> such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at <math>V_{out}</math> is 3 V when there is no input pulse.  
 
#Select <math>R_1</math> and <math>R_2</math> such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at <math>V_{out}</math> is 3 V when there is no input pulse.  
 +
 +
<math>I = \frac<V><R_1+R_2> \leq 1\ mA \rightarrow R_1+R_2 geq \frac<5\ V><1 \mA> = 5\ k\Omega</math>
 +
 
#Select a capacitor <math>(C)</math>and a pulse width \<math>tau</math>  to form a differentiating circuit for the pulse from the signal generator.  Hint: <math>R_{12}C \ll \tau</math>.  
 
#Select a capacitor <math>(C)</math>and a pulse width \<math>tau</math>  to form a differentiating circuit for the pulse from the signal generator.  Hint: <math>R_{12}C \ll \tau</math>.  
 
#plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time using your scope observations. (20 pnts)
 
#plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time using your scope observations. (20 pnts)

Revision as of 04:59, 22 February 2011

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Lab 9: Diode Circuits

Clipping Circuit

1.) Construct the circuit shown below using a silicon diode.

TF EIM Lab9.png

2.) Use a sine wave generator to drive the circuit so [math]V_{in} = V_0 \cos(2 \pi \nu t)[/math] where [math]V_0 = 0.1[/math] V and [math] \nu[/math] = 1kHz. (20 pnts)

3.)Based on your observations using a oscilloscope, sketch the voltages [math]V_{in}[/math] and [math]V_{out}[/math] as a function of time.

4.)Do another sketch for[math] V_0[/math] = 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)

Differentiating Circuit with clipping

  1. Construct the circuit below.

TF EIM Lab9a.png

  1. Select [math]R_1[/math] and [math]R_2[/math] such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at [math]V_{out}[/math] is 3 V when there is no input pulse.

[math]I = \frac\lt V\gt \lt R_1+R_2\gt \leq 1\ mA \rightarrow R_1+R_2 geq \frac\lt 5\ V\gt \lt 1 \mA\gt = 5\ k\Omega[/math]

  1. Select a capacitor [math](C)[/math]and a pulse width \[math]tau[/math] to form a differentiating circuit for the pulse from the signal generator. Hint: [math]R_{12}C \ll \tau[/math].
  2. plot [math]V_{in}[/math] and [math]V_{out}[/math] as a function of time using your scope observations. (20 pnts)
  3. Now add the diode circuit from part 1 to prevent [math]V_{out}[/math] from rising above +5 V. Sketch the new circuit below.
  4. plot [math]V_{in}[/math] and [math]V_{out}[/math] as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)

Questions

  1. Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)


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