Difference between revisions of "July, 6, 2007 Investigations of Geometry Influence on the Fission Fragments Behaviour"

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== 1. Theoretical Calculations ==
 
== 1. Theoretical Calculations ==
Relativistic charged partcles lose energy in matter primarily by ionization. The mean rate of energy loss is given by the Bethe_Bloch equation,<br>
+
Relativistic charged particles lose energy in matter primarily by ionization. The mean rate of energy loss is given by the Bethe_Bloch equation,<br>
  
-<math>\frac{dE}{dx}</math>=K<math>z^2\frac{Z}{A}</math><math>\frac{1}{\beta^2}</math>[<math>\frac{1}{2}\ln\frac{2m_ec^2\beta^2\gamma^2T_max}{I^2}</math>]
+
- <math>\frac{dE}{dx}</math>=K<math>z^2\frac{Z}{A}</math><math>\frac{1}{\beta^2}</math>[<math>\frac{1}{2}\ln\frac{2m_ec^2\beta^2\gamma^2T_{max}}{I^2}</math> - <math>\beta^2</math> - <math>\frac{\delta}{2}</math>]<br>
 +
<math>\frac{K}{A}</math> = 0.307075 MeV <math>g^{-1} cm^2</math><br>
 +
<math>T_{max}</math>=61 keV<br>
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<math>\beta</math>=0.033<br>
 +
For example, for incident particle Ce-140 and target U-238, we have following results for energy loss<br>
 +
Density of Uranium is 19.1 <math>\frac{g}{cm^3}</math>  [http://hypertextbook.com/facts/2006/MichaelMirochnik.shtml]<br>
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 +
- <math>\frac{dE}{dx}</math>=<math>0.3071*58^2*19.1</math> <math>{\frac{92}{140}} {\frac{1}{0.033^2}} \frac{1}{2}\ln[\frac{2*0.51*0.033^2*0.061}{883.2^2*10^{-12}}]</math> = 2.66 <math>\frac{MeV}{nm}</math><br>
 +
The half length <math>X_{\frac{1}{2}}</math> is the distance needed to reduce the intensity in half <br>
 +
 
 +
<math>X_{\frac{1}{2}}</math> = <math>\frac{61}{2*2.66*10^3}</math> nm = 0.0115 nm<br>
 +
 +
Time    t=<math>\frac{0.0115*10^{-9}}{0.033*3*10^8}</math> = <math>1.16*10^{-9}</math> nsec
 +
 
 +
== 2. Simulation ==
 +
 
 +
(i) Simulated half-length for totally ionized unexited Ce-140 (A=140, Z=58, Q=58, E'=0) having energy 61 keV propagated thru the U-238 target:
 +
 
 +
[[Image:Ce_attenuation_U_2.jpg]]
 +
 
 +
Half-length:
 +
 
 +
<math>X_{\frac{1}{2}} = 0.33 nm = 3.3 A </math>
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 +
Time needed to the Ce-140 ion to pass half-length:
 +
 
 +
Time = <math>3.3*10^{-17} s</math>
 +
 
 +
(ii) Energy spectrum of Ce-140 ions (E = 61 keV). Number of incident ions was 20,000:
 +
 
 +
[[Image:Energy_sp_Ce.jpg]]

Latest revision as of 00:13, 9 July 2007

1. Theoretical Calculations

Relativistic charged particles lose energy in matter primarily by ionization. The mean rate of energy loss is given by the Bethe_Bloch equation,

- [math]\frac{dE}{dx}[/math]=K[math]z^2\frac{Z}{A}[/math][math]\frac{1}{\beta^2}[/math][[math]\frac{1}{2}\ln\frac{2m_ec^2\beta^2\gamma^2T_{max}}{I^2}[/math] - [math]\beta^2[/math] - [math]\frac{\delta}{2}[/math]]
[math]\frac{K}{A}[/math] = 0.307075 MeV [math]g^{-1} cm^2[/math]
[math]T_{max}[/math]=61 keV
[math]\beta[/math]=0.033
For example, for incident particle Ce-140 and target U-238, we have following results for energy loss
Density of Uranium is 19.1 [math]\frac{g}{cm^3}[/math] [1]

- [math]\frac{dE}{dx}[/math]=[math]0.3071*58^2*19.1[/math] [math]{\frac{92}{140}} {\frac{1}{0.033^2}} \frac{1}{2}\ln[\frac{2*0.51*0.033^2*0.061}{883.2^2*10^{-12}}][/math] = 2.66 [math]\frac{MeV}{nm}[/math]
The half length [math]X_{\frac{1}{2}}[/math] is the distance needed to reduce the intensity in half

[math]X_{\frac{1}{2}}[/math] = [math]\frac{61}{2*2.66*10^3}[/math] nm = 0.0115 nm

Time t=[math]\frac{0.0115*10^{-9}}{0.033*3*10^8}[/math] = [math]1.16*10^{-9}[/math] nsec

2. Simulation

(i) Simulated half-length for totally ionized unexited Ce-140 (A=140, Z=58, Q=58, E'=0) having energy 61 keV propagated thru the U-238 target:

Ce attenuation U 2.jpg

Half-length:

[math]X_{\frac{1}{2}} = 0.33 nm = 3.3 A [/math]

Time needed to the Ce-140 ion to pass half-length:

Time = [math]3.3*10^{-17} s[/math]

(ii) Energy spectrum of Ce-140 ions (E = 61 keV). Number of incident ions was 20,000:

Energy sp Ce.jpg