Difference between revisions of "July, 6, 2007 Investigations of Geometry Influence on the Fission Fragments Behaviour"

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- <math>\frac{dE}{dx}</math>=<math>0.3071*58^2*19.1</math> <math>{\frac{92}{140}} {\frac{1}{0.033^2}} \frac{1}{2}\ln[\frac{2*0.51*0.033^2*0.061}{883.2^2*10^{-12}}]</math> = 2.66 <math>\frac{MeV}{nm}</math><br>
 
- <math>\frac{dE}{dx}</math>=<math>0.3071*58^2*19.1</math> <math>{\frac{92}{140}} {\frac{1}{0.033^2}} \frac{1}{2}\ln[\frac{2*0.51*0.033^2*0.061}{883.2^2*10^{-12}}]</math> = 2.66 <math>\frac{MeV}{nm}</math><br>
 +
The half length <math>X_{\frac{1}{2}}</math> is the distance needed to reduce the intensity in half <br>
 +
 +
<math>X_{\frac{1}{2}}</math> = <math>\frac{61}{2.66*10^3}</math>

Revision as of 21:41, 6 July 2007

1. Theoretical Calculations

Relativistic charged particles lose energy in matter primarily by ionization. The mean rate of energy loss is given by the Bethe_Bloch equation,

- [math]\frac{dE}{dx}[/math]=K[math]z^2\frac{Z}{A}[/math][math]\frac{1}{\beta^2}[/math][[math]\frac{1}{2}\ln\frac{2m_ec^2\beta^2\gamma^2T_{max}}{I^2}[/math] - [math]\beta^2[/math] - [math]\frac{\delta}{2}[/math]]
[math]\frac{K}{A}[/math] = 0.307075 MeV [math]g^{-1} cm^2[/math]
[math]T_{max}[/math]=61 keV
[math]\beta[/math]=0.033
For example, for incident particle Ce-140 and target U-238, we have following results for energy loss
Density of Uranium is 19.1 [math]\frac{g}{cm^3}[/math] [1]

- [math]\frac{dE}{dx}[/math]=[math]0.3071*58^2*19.1[/math] [math]{\frac{92}{140}} {\frac{1}{0.033^2}} \frac{1}{2}\ln[\frac{2*0.51*0.033^2*0.061}{883.2^2*10^{-12}}][/math] = 2.66 [math]\frac{MeV}{nm}[/math]
The half length [math]X_{\frac{1}{2}}[/math] is the distance needed to reduce the intensity in half

[math]X_{\frac{1}{2}}[/math] = [math]\frac{61}{2.66*10^3}[/math]