Difference between revisions of "In the Detector Frame"

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(Created page with " We can define the constraints of the plane the DC is in <pre> right = ContourPlot[ x2 == Cot[29.5 \[Degree]] y + .09156, {y, -1, 1}, {x2, 0, 1.8}, Frame -> {True, True, …")
 
 
(13 intermediate revisions by the same user not shown)
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<center><math>\underline{\textbf{Navigation}}</math>
  
We can define the constraints of the plane the DC is in
+
[[Wire_Number_Function|<math>\vartriangleleft </math>]]
 +
[[VanWasshenova_Thesis#Determining_wire-theta_correspondence|<math>\triangle </math>]]
 +
[[The_Wires|<math>\vartriangleright </math>]]
  
<pre>
+
</center>
right = ContourPlot[
 
  x2 == Cot[29.5 \[Degree]] y + .09156, {y, -1, 1}, {x2, 0, 1.8},
 
  Frame -> {True, True, False, False},
 
  PlotLabel -> "Right side limit of DC as a function of X and Y",
 
  FrameLabel -> {"y (meters)", "x (meters)"}, ContourStyle -> Black,
 
  PlotLegends -> Automatic];
 
  
left = ContourPlot[
+
<center>[[File:Part1d1.png]]</center>
  x2 == -Cot[29.5 \[Degree]] y + .09156, {y, -1, 1}, {x2, 0, 1.8},
 
  Frame -> {True, True, False, False},
 
  PlotLabel -> "Right side limit of DC as a function of X and Y",
 
  FrameLabel -> {"y (meters)", "x (meters)"}, ContourStyle -> Black,
 
  PlotLegends -> Automatic];
 
  
</pre>
 
  
 +
----
  
We can define the x coordinate of the wires as they cross the midpoint plane as shown earlier.
 
  
<pre>
+
<center><math>\underline{\textbf{Navigation}}</math>
x0forWires[number_] := .23168 + .01337*(number);
 
</pre>
 
  
 +
[[Wire_Number_Function|<math>\vartriangleleft </math>]]
 +
[[VanWasshenova_Thesis#Determining_wire-theta_correspondence|<math>\triangle </math>]]
 +
[[The_Wires|<math>\vartriangleright </math>]]
  
We can define the point midway between two parallel lines as the point where one wire is recorded versus its next highest neighbor
+
</center>
 
 
<pre>
 
x0forWireMiddles[
 
  number_] := ((.23168 + .01337*(number)) + (.23168 + .01337*(number \
 
+ 1)))/2;
 
</pre>
 
 
 
All of the conditions dependent on <math> \theta </math> and <math>\phi</math>
 
 
 
<pre>
 
 
 
\[CapitalDelta]a :=
 
  FullSimplify[(R Sin[\[Theta] \[Degree]])/
 
    2 (Csc[65 \[Degree] - \[Theta] \[Degree]] -
 
      Csc[115 \[Degree] - \[Theta] \[Degree]]), \[Theta] > 0];
 
e := Sin[25 \[Degree]]/Cos[\[Theta] \[Degree]];
 
a := FullSimplify[(R Sin[\[Theta] \[Degree]])/
 
    2 (Csc[65 \[Degree] - \[Theta] \[Degree]] +
 
      Csc[115 \[Degree] - \[Theta] \[Degree]]), \[Theta] > 0];
 
rD1 := Simplify[(a e - \[CapitalDelta]a) Tan[
 
    65 \[Degree]] Cos[\[Theta] \[Degree]], \[Theta] > 0];
 
rD2 := Simplify[(a e + \[CapitalDelta]a) Tan[
 
    65 \[Degree]] Cos[\[Theta] \[Degree]], \[Theta] > 0];
 
xD1 := Simplify[rD1 Cos[\[Phi] \[Degree]]];
 
yD1 := Simplify[rD1 Sin[\[Phi] \[Degree]]];
 
zD1 := Simplify[rD1 Cot[\[Theta] \[Degree]], \[Theta] > 0];
 
xD2 := Simplify[rD2 Cos[\[Phi] \[Degree]], \[Theta] > 0];
 
yD2 := Simplify[rD2 Sin[\[Phi] \[Degree]], \[Theta] > 0];
 
zD2 := Simplify[rD2 Cot[\[Theta] \[Degree]], \[Theta] > 0];
 
xP := Simplify[(R Cos[\[Phi] \[Degree]])/(Cot[\[Theta] \[Degree]] +
 
      Cos[\[Phi] \[Degree]] Cot[65 \[Degree]]), \[Theta] > 0];
 
yP := Simplify[(R Sin[\[Phi] \[Degree]])/(Cot[\[Theta] \[Degree]] +
 
      Cos[\[Phi] \[Degree]] Cot[65 \[Degree]]), \[Theta] > 0];
 
zP := Simplify[(R Cot[\[Theta] \[Degree]])/(Cot[\[Theta] \[Degree]] +
 
      Cos[\[Phi] \[Degree]] Cot[65 \[Degree]]), \[Theta] > 0];
 
x1 := Simplify[(rD2^2 - rD1^2 +
 
      Cot[\[Theta] \[Degree]]^2 (rD2^2 - rD1^2) - 2 xP (xD2 - xD1) -
 
      2 yP (yD2 - yD1) - 2 zP (zD2 - zD1))/(4 a e) - a e, \[Theta] >
 
    0];
 
x := Simplify[x1 - \[CapitalDelta]a + a e, \[Theta] > 0];
 
xCenter := x + \[CapitalDelta]a;
 
n := -957.412/(Tan[\[Theta] \[Degree]] + 2.14437) + 430.626;
 
D2P := Simplify[((xD2 - xP)^2 + (yD2 - yP)^2 + (zD2 -
 
      zP )^2)^.5, \[Theta] > 0] // N
 
D1P := Simplify[((xP - xD1)^2 + (yP - yD1)^2 + (zP -
 
        zD1)^2)^.5, \[Theta] > 0] // N;
 
y := Simplify[(D1P^2 - x1^2)^.5, \[Theta] > 0] // N;
 
b := Simplify[a Sqrt[1 - e^2], \[Theta] > 0] // N;
 
R = 2.52934271645;
 
</pre>
 
 
 
We can define the x-y position on the DC plane as a function of <math>\phi</math> for and limit the angles with the wall on the right and left hand sides.  By symmetry these angles are equal, but opposite in sign. 
 
 
 
<pre>
 
Limits = Table[\[Phi] /.
 
    NSolve[Sqrt[a^2 (1 - y^2/b^2)] - \[CapitalDelta]a ==
 
      Cot[29.5 \[Degree]] y + .09156 , \[Phi]], {\[Theta], 5, 40}];
 
Lim = Table[0, {rows, 1, 36}];
 
For[rows = 1, rows < 37, rows++,
 
  For[i = 1, i < 5, i++,
 
    If[Limits[[rows, i]] > 0 && Limits[[rows, i]] < 40,
 
      Lim[[rows]] = Limits[[rows, i]];
 
      ];
 
    ];
 
  ];
 
</pre>
 
 
 
The angle must have 4 subtracted to equal the line element numbering
 
 
 
<pre>
 
In[33]:= Lim[[7 - 4]]
 
 
 
Out[33]= 23.4101
 
</pre>
 
 
 
The limit of <math>\phi</math> increases in the plane of the DC sector changes as <math>\theta</math> increases.
 
 
 
<pre>
 
In[34]:= Lim[1]
 
 
 
Out[34]= {20.076, 22.024, 23.4101, 24.448, 25.255, 25.9008, 26.4297,
 
  26.8711, 27.2453, 27.5667, 27.846, 28.0911, 28.3079, 28.5013,
 
  28.675, 28.8319, 28.9744, 29.1044, 29.2237, 29.3336, 29.4352,
 
  29.5294, 29.6171, 29.699, 29.7757, 29.8477, 29.9155, 29.9795,
 
  30.0399, 30.0973, 30.1517, 30.2034, 30.2528, 30.2999, 30.3449,
 
  30.388}[1]
 
</pre>
 
 
 
This limiting condition will record the angle <math>\phi</math> in degrees within an array of wire number(1-112) horizontally  and angle <math>\theta (5^{\circ}-40^{\circ} )</math> vertically
 
 
 
<pre>
 
RightSolutions =
 
  Table[{\[Phi] /.
 
    Solve[Sqrt[a^2 (1 - y^2/b^2)] - \[CapitalDelta]a ==
 
      Tan[6 \[Degree]] y +
 
        x0forWireMiddles[number]  , \[Phi]]}, {\[Theta], 5,
 
    40}, {number, 1, 112}];
 
LineRight = Table[{\[Phi], columns}, {rows, 1, 36}, {columns, 1, 112}];
 
For[rows = 1, rows < 37, rows++,
 
  For[columns = 1, columns < 113, columns++,
 
    For[i = 1, i < 5, i++,
 
      If[RightSolutions[[rows, columns, 1, i]] > 0  &&
 
        RightSolutions[[rows, columns, 1, i]] < Lim[[rows]],
 
        LineRight[[rows,
 
          columns]] = {RightSolutions[[rows, columns, 1, i]],
 
          columns + .5};
 
        ];
 
      ];
 
    ];
 
  ];
 
</pre>
 
 
 
At <math>\phi </math>=0, the condition of n=-959.637/(tan <math>\theta^{\circ}</math> +2.14437)+430.189  should be met
 
 
 
<pre>
 
In[38]:= f[\[Theta]for\[Phi]at0_] := -959.637/(
 
  Tan[\[Theta]for\[Phi]at0 \[Degree]] + 2.14437) + 430.189
 
 
 
In[39]:= f[40]
 
 
 
Out[39]= 108.538
 
</pre>
 
 
 
 
 
This implies that for <math>\theta=40^{\circ}</math>, we know that the wire number to be 108.538.  This corresponds to the position being in between 108.5 and 109.5, hence it falls into the 109 "bin". 
 
 
 
Testing the geometry
 
<pre>
 
ClearAll[\[Theta]];
 
\[Theta] = 40;
 
ellipse40 =
 
  ContourPlot[(x + \[CapitalDelta]a)^2/a^2 + y^2/b^2 == 1, {y, -1,
 
    1}, {x, 1.2, 1.7}, Frame -> {True, True, False, False},
 
  PlotLabel ->
 
    "XY position on DC as a function of \[Phi] for \[Theta]=40\
 
\[Degree]", FrameLabel -> {"y (meters)", "x (meters)"},
 
  ContourStyle -> Red, PlotLegends -> Automatic];
 
Show[Table[
 
  ContourPlot[
 
  xWire == Tan[6 \[Degree]] yWire + x0forWires[number], {yWire, -1,
 
    1}, {xWire, 1.2, 1.7},
 
  FrameLabel -> {"y(meters)", "x(meters)"}], {number, 70, 109}],
 
Table[ContourPlot[
 
  xWire ==
 
    Tan[6 \[Degree]] yWire + x0forWireMiddles[number2], {yWire, -1,
 
    1}, {xWire, 1.2, 1.7},
 
  ContourStyle -> {Dashing[Large]}], {number2, 70,
 
  109}], bottom, right, left, ellipse40]
 
</pre>
 
 
 
[[File:40EllipseTest.png]]
 

Latest revision as of 20:32, 15 May 2018