Difference between revisions of "Geometry (25 MeV LINAC exit port)"

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=Minimum accelerator energy to run experiment=
 
=Minimum accelerator energy to run experiment=
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==<math>x_2 + r_2<= R</math> condition==
  
 
[[File:min_energy.png|1000px]]
 
[[File:min_energy.png|1000px]]
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       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  </math>
 
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  </math>
  
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4) In general:
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4) for arbitrary collimator size:
  
 
[[File:plot_energy_collimatorsize.jpeg]]
 
[[File:plot_energy_collimatorsize.jpeg]]
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All energy above this line is good to run experiment
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==<math>F_1A <= 286\ cm</math> condition==
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[[File:plot_energy_F1A.jpeg]]
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All energy above this line is good to run experiment
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==both condition above just together==
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[[File:plot_energy_bothcondition.jpeg]]
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All energy above this lines is good to run experiment
  
 
=25 MeV geometry=
 
=25 MeV geometry=

Revision as of 18:29, 14 June 2010

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Minimum accelerator energy to run experiment

[math]x_2 + r_2\lt = R[/math] condition

Min energy.png

The minimum energy of accelerator (MeV) is limited by fitting the collimator ([math]r_2[/math]) into the hole ([math]R = 8.73\ cm[/math]) 

[math]x_2 + r_2 = R[/math]

1) Assuming the collimator diameter is [math]\Theta_C[/math]: 

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 33.1\ MeV  [/math]

2) Assuming the collimator diameter is [math]\Theta_C/2[/math]: 

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{2}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 26.3\ MeV  [/math]

3) Assuming the collimator diameter is [math]\Theta_C/4[/math]: 

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  [/math]

4) for arbitrary collimator size:

Plot energy collimatorsize.jpeg

All energy above this line is good to run experiment


[math]F_1A \lt = 286\ cm[/math] condition

Plot energy F1A.jpeg

All energy above this line is good to run experiment


both condition above just together

Plot energy bothcondition.jpeg

All energy above this lines is good to run experiment

25 MeV geometry

geometry calculation

collimator diameter [math]\Theta_{critical}[/math] [math]\Theta_{kicker}[/math] [math]\alpha_{collimator}[/math] [math]AC[/math] [math]A_1C_1[/math] [math]BD[/math] [math]B_1D_1[/math] [math]FA[/math] [math]F_1F[/math]
[math]\frac{\Theta_{critical}}{2}[/math] [math]1.17^o[/math] [math]0.83^o[/math] [math]2.03^o[/math] 4.13 cm 6.78 cm 2.92 cm 4.79 cm 75 cm 143 cm
[math]\frac{\Theta_{critical}}{4}[/math] [math]1.17^o[/math] [math]0.83^o[/math] [math]1.43^o[/math] 4.13 cm 6.78 cm 1.46 cm 2.40 cm 136 cm 203 cm

geometry pictures

how it looks 1 ([math] \Theta_c/2[/math], box 3"x4" and then pipe 4")

File:Vacuum pipe collimator .png

how it looks 2 ([math] \Theta_c/4[/math], box 3"x4" and then pipe 4")

File:Vacuum pipe collimator .png


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