Difference between revisions of "Forest UCM MnAM ElasticCol"

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;Conservation of momentum
 
;Conservation of momentum
  
:<math>m_1 \vec{v}_1 + m_2 \vec{v}_2= m_1 \vec{v}_1^{\prime} +m_2 \vec{v}_2^{;;\prime}</math>
+
:<math>m_1 \vec{v}_1 + m_2 \vec{v}_2= m_1 \vec{v}_1^{\prime} +m_2 \vec{v}_2^{\;\;\prime}</math>
:<math>m_1 \vec{v}_1 = m_1 \vec{v}_1^{;\prime} +m_2 \vec{v}_2^{\prime}</math>: ball 2 has zero velocity
+
:<math>m_1 \vec{v}_1 = m_1 \vec{v}_1^{\;\prime} +m_2 \vec{v}_2^{\prime}</math>: ball 2 has zero velocity
:<math>\vec{v}_1 =  \vec{v}_1^{;;;\prime} + \vec{v}_2^{\prime}</math>: balls have equal masses
+
:<math>\vec{v}_1 =  \vec{v}_1^{\;\;\;\prime} + \vec{v}_2^{\prime}</math>: balls have equal masses
  
  

Revision as of 12:15, 12 September 2014

An Elastic collision conserves both Momentum and Energy

[math]\vec{P}_{\mbox{initial}} = \vec{P}_{\mbox{final}}[/math]
AND
[math]E_{\mbox{initial}} = E_{\mbox{final}}[/math]

Example: problem 3.5

Consider an elastic collision of two equal balls of mass [math]m[/math] where one ball has an initial velocity [math]\vec{v}_1[/math] and the remaining ball has zero initial velocity.

Determine the angle between the two balls after the collision.


Conservation of momentum
[math]m_1 \vec{v}_1 + m_2 \vec{v}_2= m_1 \vec{v}_1^{\prime} +m_2 \vec{v}_2^{\;\;\prime}[/math]
[math]m_1 \vec{v}_1 = m_1 \vec{v}_1^{\;\prime} +m_2 \vec{v}_2^{\prime}[/math]: ball 2 has zero velocity
[math]\vec{v}_1 = \vec{v}_1^{\;\;\;\prime} + \vec{v}_2^{\prime}[/math]: balls have equal masses


Conservation of energy
m_1 v_1^2 + m_2 v_2^2 = m_1 \left(v_1^{\prime}\right)^2 + m_2\left(v_2^{\prime}\right)^2
v_1^2 = \left(v_1^{\prime}\right)^2 + \left(v_2^{\prime}\right)^2



Forest_UCM_MnAM#Elastic_Collision_of_2_bodies