Difference between revisions of "Forest UCM Ch3 CoM"

From New IAC Wiki
Jump to navigation Jump to search
Line 24: Line 24:
 
:<math>\vec{r}_3 = (0,0,0) = \vec{0}</math>
 
:<math>\vec{r}_3 = (0,0,0) = \vec{0}</math>
 
when  
 
when  
:<math>m_1 = m_2 = m_3/10</math>
+
:<math>m_1 = m_2 = 3 m_3</math>
  
  
Line 30: Line 30:
 
<math> m_3 = M</math>
 
<math> m_3 = M</math>
  
:<math>\vec{R} = \frac{10M (1) + 10 M (1) + M(0)}{21M} \hat i  + \frac{10M (1) + 10 M (-1) + M(0)}{21M} \hat j</math>
+
:<math>\vec{R} = \frac{3M (1) + 3 M (1) + M(0)}{5M} \hat i  + \frac{3M (1) + 3 M (-1) + M(0)}{5M} \hat j</math>
:<math>\vec{R} = \frac{20}{21} \hat i  + \frac{0}{21M} \hat j</math>
+
:<math>\vec{R} = \frac{6}{5} \hat i  + \frac{0}{5M} \hat j</math>
  
 
=Example 2: CM of a flat disk=
 
=Example 2: CM of a flat disk=

Revision as of 14:22, 13 September 2014

The Center of mass

Definition of the Center of Mass

The position [math]\vec R[/math] of the center of mass is given by

[math]\vec{R} = \frac{\sum_i^N m_i \vec{r}_i}{\sum_i^N m_i}[/math]


The center of mass is given as the sum of the position of each object in the system weighted by the objects mass.


For a rigid object the location of the center of mass is given by


[math]\vec{R} = \frac{1}{M} \int \vec{r} dm[/math]

Example 1: CM of three particles

Calculate the location of the center of mass given the three particles below

[math]\vec{r}_1 = (1,1,0) = \hat i + \hat j[/math]
[math]\vec{r}_2 = (1,-1,0) = \hat i - \hat j[/math]
[math]\vec{r}_3 = (0,0,0) = \vec{0}[/math]

when

[math]m_1 = m_2 = 3 m_3[/math]


let [math] m_3 = M[/math]

[math]\vec{R} = \frac{3M (1) + 3 M (1) + M(0)}{5M} \hat i + \frac{3M (1) + 3 M (-1) + M(0)}{5M} \hat j[/math]
[math]\vec{R} = \frac{6}{5} \hat i + \frac{0}{5M} \hat j[/math]

Example 2: CM of a flat disk

Example 3: CM of a semicircle

Forest_UCM_MnAM#Center_of_Mass