Difference between revisions of "Doppler Broadening"

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'''Our Calculations'''<br>
 
'''Our Calculations'''<br>
  
E=2617 keV, v=<math>10^9</math> cm/s, speed of light c=3X<math>10^10</math> cm/s
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For example for energy E=2617 keV and the fragment velocity v=<math>10^9</math> cm/s, speed of light c=3X<math>10^{10}</math> cm/s, <math>beta</math>=0.033 we have
  
 
== Photon emission off fission fragment velocity axis==
 
== Photon emission off fission fragment velocity axis==

Revision as of 19:17, 25 June 2007

Theory of Dopler Broadening

Photon emmision along direction of fission fragment velocit

[math]E_{shift} = E_{photon} \frac{1-\beta \cos(\theta_{photon}^i)}{\sqrt{1-\beta_i^2}}[/math] = amount of energy the gamma ray was shifted by

where [math]E_{photon}[/math] is the Doppler-shifted [math]\gamma[/math]-ray energy which was measured


[math]cos\theta_{photon1}[/math]=-[math]cos\theta_{1}[/math] for an excited fragment in det-1
[math]cos\theta_{photon2}[/math]=-[math]cos\theta_{2}[/math] for an excited fragment in det-2


[math]\theta_i[/math] is the polar emission angle of excited fragment and [math]\beta_i[/math] the fragment velocity

[math]\beta_i[/math]=0.04634[math]\sqrt{\frac{E_i[MeV]}{A_i[u]}}[/math]


Our Calculations

For example for energy E=2617 keV and the fragment velocity v=[math]10^9[/math] cm/s, speed of light c=3X[math]10^{10}[/math] cm/s, [math]beta[/math]=0.033 we have

Photon emission off fission fragment velocity axis

Cf-252 Fission

Photon Spectra from Cf-252

Photon spectrum.jpg


References: http://prola.aps.org/pdf/PR/v104/i3/p699_1

Smith, A. B.; Fields, P. R.; Friedman A. M., Physical Review, vol. 104, Issue 3, pp. 699 - 702

Measurements in the Beam test lab with HpGe and BC408

June 15,2007 Cf-252 measurements with HpGe & neutron sensitive scintillators in coincidence
June 19,2007 Cf-252 measurements with HpGe & neutron sensitive scintillators in coincidence
June 19,2007 Cf-252 measurements of gamma-spectrum using HpGe ungated