Difference between revisions of "Differential Cross-Section"

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<center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(p_A+p_C)_{\mu}(p_B+p_D)^{\mu}}{(p_D-p_B)^2}- \frac{e^2(p_A+p_D)_{\mu}(p_B+p_C)^{\mu}}{(p_C-p_B)^2} \right )</math></center>
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<center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(\mathbf p_A+\mathbf p_C)_{\mu}(\mathbf p_B+\mathbf p_D)^{\mu}}{(\mathbf p_D-\mathbf p_B)^2}- \frac{e^2(\mathbf p_A+\mathbf p_D)_{\mu}(p_B+p_C)^{\mu}}{(p_C-p_B)^2} \right )</math></center>
  
  
<center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{(p_Ap_B+p_Cp_D+p_Cp_B+p_Ap_D}{(p_D-p_B)^2}- \frac{(p_Ap_B+p_Dp_C+p_Dp_B+p_Ap_C}{(p_C-p_B)^2} \right )</math></center>
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<center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{(\mathbf p_A \mathbf p_B+\mathbf p_C \mathbf p_D+\mathbf p_C \mathbf p_B+\mathbf p_A \mathbf p_D}{(\mathbf p_D-\mathbf p_B)^2}- \frac{(\mathbf p_A \mathbf p_B+\mathbf p_D \mathbf p_C+\mathbf p_D \mathbf p_B+\mathbf p_A \mathbf p_C}{(\mathbf p_C-\mathbf p_B)^2} \right )</math></center>
  
  
  
 
<center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center>
 
<center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center>

Revision as of 14:55, 24 June 2017

[math]-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(\mathbf p_A+\mathbf p_C)_{\mu}(\mathbf p_B+\mathbf p_D)^{\mu}}{(\mathbf p_D-\mathbf p_B)^2}- \frac{e^2(\mathbf p_A+\mathbf p_D)_{\mu}(p_B+p_C)^{\mu}}{(p_C-p_B)^2} \right )[/math]


[math] \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{(\mathbf p_A \mathbf p_B+\mathbf p_C \mathbf p_D+\mathbf p_C \mathbf p_B+\mathbf p_A \mathbf p_D}{(\mathbf p_D-\mathbf p_B)^2}- \frac{(\mathbf p_A \mathbf p_B+\mathbf p_D \mathbf p_C+\mathbf p_D \mathbf p_B+\mathbf p_A \mathbf p_C}{(\mathbf p_C-\mathbf p_B)^2} \right )[/math]


[math]\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )[/math]