Difference between revisions of "Determining wire-phi correspondance"

From New IAC Wiki
Jump to navigation Jump to search
Line 17: Line 17:
 
Following the rules of conic sections we know that the eccentricity of the conic is given by:
 
Following the rules of conic sections we know that the eccentricity of the conic is given by:
  
<center><math>e=\frac{\sin [\beta]}{\sin[\alpha]}</math></center>
+
<center><math>e=\frac{\sin \beta}{\sin\alpha}</math></center>
  
  

Revision as of 05:19, 3 January 2017

DC stereo.png


Using Mathematica, we can produce a 3D rendering of how the sectors for Level 1 would have to interact with a steady angle theta with respect to the beam line, as angle phi is rotated through 360 degrees.

PhiCone.png


Looking just at sector 1, we can see that the intersection of level 1 and the cone of constant angle theta forms a conic section.

Projection side view.png


Projection Rear view.png


Following the rules of conic sections we know that the eccentricity of the conic is given by:

[math]e=\frac{\sin \beta}{\sin\alpha}[/math]


Where β is the angle of the plane, and α is the slant of the cone.

If the conic is an circle, e=0

If the conic is an parabola, e=1

If the conic is an ellipse, [math]e=\sqrt{1-\frac{b^2}{a^2}}[/math]

File:Conic section.png.png