DV MollerTrackRecon

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Moller events No Solenoid

LUND file with Moller events (with origin of coordinates occurring at each event)

2       1       1       1       1       0       0.000563654     3.53715 0       6.2002
1 -1 1 11 0 0 0.69 -2.4999 10993.7998 10993.80 0.000511 0 0 0
2 -1 1 11 0 0 -0.69 2.4999 6.5852 7.08 0.000511 0 0 0
2       1       1       1       1       0.650745        0.00159988      3.52285 21.4844 17.5986
1 -1 1 11 0 0 -4.20 0.3862 10982.4004 10982.40 0.000511 -0.000456454 0.00077441 0
2 -1 1 11 0 0 3.45 0.8800 12.4191 12.92 0.000511 -0.000456454 0.00077441 0
2       1       1       1       1       0.650745        0.00159988      3.52285 21.4844 17.5986
1 -1 1 11 0 0 -4.20 0.3862 10982.4004 10982.40 0.000511 -0.000456454 0.00077441 0
2 -1 1 11 0 0 0.75 -1.2666 2.1155 2.58 0.000511 0 0 0

Analysis event29.png

Picture of ced output for event 29

Simulation

Event29 1.png

Reconstruction

No sol1.png

Simulation

Event29 2.png

Reconstruction

No sol2.png

Simulation

Event29 3.png

Reconstruction

No sol3.png

EulerAngles.png

Transformation Matrix

[math]\left( \begin{array}{ccc} \cos (\theta ) & 0 & -\sin (\theta ) \\ 0 & 1 & 0 \\ \sin (\theta ) & 0 & \cos (\theta ) \\ \end{array} \right).\left( \begin{array}{c} x \\ y \\ z \\ \end{array} \right)[/math]


[math]=\left( \begin{array}{c} x \cos (\theta )-z \sin (\theta ) \\ y \\ z \cos (\theta )+x \sin (\theta ) \\ \end{array} \right)[/math]


For event #29, in sector 3, the location of the first interaction is given by

Conversions.png


Converting -25 degrees to radians, [math]\theta =-0.436332[/math]


[math]\left( \begin{array}{ccc} \cos (\theta ) & 0 & -\sin (\theta ) \\ 0 & 1 & 0 \\ \sin (\theta ) & 0 & \cos (\theta ) \\ \end{array} \right).\left( \begin{array}{c} -15.76 \\ 0 \\ 237.43 \\ \end{array} \right)[/math]

[math]=\left( \begin{array}{c} 86.0588 \\ 0. \\ 221.845 \\ \end{array} \right)[/math]

Finding [math]\phi =\frac{120\ 2 \pi }{360};[/math] since "sector -1" =3-1=2*60=120 degrees

[math]\left( \begin{array}{ccc} \cos (\phi ) & -\sin (\phi ) & 0 \\ \sin (\phi ) & \cos (\phi ) & 0 \\ 0 & 0 & 1 \\ \end{array} \right).\left( \begin{array}{c} 86.0588 \\ 0. \\ 221.845 \\ \end{array} \right)[/math]

[math]\left( \begin{array}{c} -43.0294 \\ 74.5291 \\ 221.845 \\ \end{array} \right)[/math]

DV_RunGroupC_Moller#Moller_Track_Reconstruction