Difference between revisions of "Counts Rate (44 MeV LINAC)"

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==steps together...==
 
==steps together...==
<math>0.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.63 \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
+
<math>0.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.64 \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
  
 
=number of neutrons in 1 second=
 
=number of neutrons in 1 second=
  
 
=geometrical factor, isotropic case=
 
=geometrical factor, isotropic case=

Revision as of 20:55, 17 May 2010

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LINAC parameters used in calculations

1) pulse width 50 ns
2) pulse current 50 A
3) repetition rate 300 Hz
4) energy 44 MeV

Number of electrons/sec on radiator

[math] 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}[/math]

Number of photons/sec from radiator

bremsstrahlung

from plot above in (10 MeV,20 MeV) region we have about

    0.1 photons/electrons/MeV/r.l

radiation length

radiation length of Ti(Z=22) is 3.59 cm
Assume the radiator thickness is [math]12.5 \mu m[/math]
[math]3.59 cm/12.5\mu m = 3.48 \cdot 10^{-4} \ r.l.[/math]

steps together...

[math]0.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.64 \cdot 10^{9} \frac{\gamma}{sec}[/math]

number of neutrons in 1 second

geometrical factor, isotropic case