Difference between revisions of "Counts Rate (44 MeV LINAC)"

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4) energy 44 MeV <br>
 
4) energy 44 MeV <br>
  
=number of electrons/sec on radiator=
+
=Number of electrons/sec on radiator=
 
<math> 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}</math><br><br>
 
<math> 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}</math><br><br>
  
=number of photons/sec from radiator=
+
=Number of photons/sec from radiator=
  
==Bremsstrahlung==
+
==bremsstrahlung==
from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region
+
from plot above in (10 MeV,20 MeV) region we hav about<br>
 +
    0.1 photons/electrons/MeV/r.l
  
==Radiation length==
+
==radiation length==
 
radiation length of Ti(Z=22)is 3.59 cm<br>     
 
radiation length of Ti(Z=22)is 3.59 cm<br>     
Assume the radiator thickness is <math>12.5 \mu m</math><br><br>
+
Assume the radiator thickness is <math>12.5 \mu m</math><br>
<math>3.59 cm/12.5\mu m = 3.48 \cdot 10^{-4} \ r.l.</math><br>
+
<math>3.59 cm/12.5\mu m = 3.48 \cdot 10^{-4} \ r.l.</math>
  
==steps together==
+
==steps together...==
 
<math>o.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.63 \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
 
<math>o.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.63 \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
  

Revision as of 20:53, 17 May 2010

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LINAC parameters used in calculations

1) pulse width 50 ns
2) pulse current 50 A
3) repetition rate 300 Hz
4) energy 44 MeV

Number of electrons/sec on radiator

[math] 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}[/math]

Number of photons/sec from radiator

bremsstrahlung

from plot above in (10 MeV,20 MeV) region we hav about

    0.1 photons/electrons/MeV/r.l

radiation length

radiation length of Ti(Z=22)is 3.59 cm
Assume the radiator thickness is [math]12.5 \mu m[/math]
[math]3.59 cm/12.5\mu m = 3.48 \cdot 10^{-4} \ r.l.[/math]

steps together...

[math]o.1 \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 3.48 \cdot 10^{-4} r.l. \times 10\ MeV \times 0.47 \cdot 10^{13} \frac{e^-}{sec}=1.63 \cdot 10^{9} \frac{\gamma}{sec}[/math]

number of neutrons in 1 second

geometrical factor, isotropic case