Difference between revisions of "Counts Rate (44 MeV LINAC)"

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from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region
 
from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region
 
==Radiation length==
 
==Radiation length==
<math>_{22}</math>Ti --> density is 4.506 g/cm^3 <br>
+
<math>_{22}</math>Ti
                      --> radiation length is 16.17 g/cm^2     
+
    --> density is 4.506 g/cm^3 <br>
 +
    --> radiation length is 16.17 g/cm^2     
 
Assume the radiator thickness is <math>12.5 /mu m</math><br>
 
Assume the radiator thickness is <math>12.5 /mu m</math><br>
  
  
====
+
== ==
 
<math>10^{-3} \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 2 \cdot 10^{-4} r.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}</math><br><br>
 
<math>10^{-3} \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 2 \cdot 10^{-4} r.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}</math><br><br>
  

Revision as of 20:33, 17 May 2010

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LINAC parameters used in calculations

1) pulse width 50 ns
2) pulse current 50 A
3) repetition rate 300 Hz
4) energy 44 MeV

number of electrons/sec on radiator

[math] 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}[/math]

number of photons/sec from radiator

Bremsstrahlung

from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region

Radiation length

[math]_{22}[/math]Ti

   --> density is 4.506 g/cm^3 
--> radiation length is 16.17 g/cm^2

Assume the radiator thickness is [math]12.5 /mu m[/math]


[math]10^{-3} \frac{\gamma 's}{(e^-\ MeV\ r.l.)} \times 2 \cdot 10^{-4} r.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}[/math]

number of neutrons in 1 second

geometrical factor, isotropic case