Difference between revisions of "Counts Rate (44 MeV LINAC)"

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=Charge/pulse 5ns (width 50ps, Current 100A), 44MeV=
 
=Charge/pulse 5ns (width 50ps, Current 100A), 44MeV=
  
1) number of electrons in 1 second:
+
1) number of electrons in 1 second:<br><br>
 
<math> 50nC \times 120Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.375 \cdot 10^{13} \frac{e^-}{sec}
 
<math> 50nC \times 120Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.375 \cdot 10^{13} \frac{e^-}{sec}
</math><br>
+
</math><br><br>
  
2) number of gammas in 1 second:
+
2) number of gammas in 1 second:<br><br>
<math>10^{-3} \frac{\gamma 's/MeV}{e^-/r.d.l.} \times 2 \cdot 10^{-4} r.d.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}</math><br>
+
<math>10^{-3} \frac{\gamma 's/MeV}{e^-/r.d.l.} \times 2 \cdot 10^{-4} r.d.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}</math><br><br>
  
 
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Revision as of 15:42, 14 May 2010

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Charge/pulse 5ns (width 50ps, Current 100A), 44MeV

1) number of electrons in 1 second:

[math] 50nC \times 120Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.375 \cdot 10^{13} \frac{e^-}{sec} [/math]

2) number of gammas in 1 second:

[math]10^{-3} \frac{\gamma 's/MeV}{e^-/r.d.l.} \times 2 \cdot 10^{-4} r.d.l. \times 44 MeV \times 0.375 \cdot 10^{12} \frac{e^-}{sec}=0.3 \cdot 10^{7} \frac{\gamma}{sec}[/math]

3)