Difference between revisions of "BO-08-22-13"

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:<math>=\left [(1.008665 u) - 196.9665516 u+ 195.9665513 u\right ] \frac{931.5 MeV}{u} = 5.3 MeV</math>
 
:<math>=\left [(1.008665 u) - 196.9665516 u+ 195.9665513 u\right ] \frac{931.5 MeV}{u} = 5.3 MeV</math>
  
==;Single proton knockout==
+
==Single proton knockout==
 
<math>{137 \atop\; }Ba (\gamma,p){136 \atop \; }Cs</math>
 
<math>{137 \atop\; }Ba (\gamma,p){136 \atop \; }Cs</math>
  

Revision as of 22:29, 4 September 2013

naturally occurring Isotope and their abundance

[math]{138 \atop\; }Ba(72%), {137 \atop\; }Ba(11%),{136 \atop\; }Ba (7.9%), {135 \atop\; }Ba(7%), {134 \atop\; }Ba(2%)[/math]

Single neutron knockout

[math]{137 \atop\; }Ba (\gamma,8){136 \atop \; }Ba[/math]


Neutron Separation Energy= Energy needed to liberate a neutron from the Nucleus

=[math]S_n = B({138 \atop 56} Au_{118})-B({{136} \atop 55} Au_{117})[/math]
[math]\left [79(1.007825 u) + 118 (1.008665 u) - 196.97 u\right ] \frac{931.5 MeV}{u} -\left [79(1.007825 u) + 117 (1.008665 u) - 195.967 u\right ] \frac{931.5 MeV}{u}[/math]
[math]=\left [(1.008665 u) - 196.9665516 u+ 195.9665513 u\right ] \frac{931.5 MeV}{u} = 5.3 MeV[/math]

Single proton knockout

[math]{137 \atop\; }Ba (\gamma,p){136 \atop \; }Cs[/math]

Cs-136

1.2 MeV

PAA_8-22-13