Difference between revisions of "BO-08-22-13"

Revision as of 19:15, 4 September 2013

naturally occurring Isotope and their abundance

{138 \atop\; }Ba(72%), {137 \atop\; }Ba(11%),{136 \atop\; }Ba (7.9%),  {135 \atop\; }Ba(7%),  {134 \atop\; }Ba(2%),

Neutron Separation Energy= Energy needed to liberate a neutron from the Nucleus

=

Cs-136

1.2 MeV

@@ Line 1: / Line 1: @@
-<math>{138 \atop\; }Ba (\gamma,n){136 \atop \; }Cs</math>
+naturally occurring Isotope and their abundance
+ {138 \atop\; }Ba(72%), {137 \atop\; }Ba(11%),{136 \atop\; }Ba (7.9%),  {135 \atop\; }Ba(7%),  {134 \atop\; }Ba(2%),
+;Single neutron knockout
+<math>{137 \atop\; }Ba (\gamma,8){136 \atop \; }Cs</math>
+<math>{137 \atop\; }Ba (\gamma,p){136 \atop \; }Cs</math>
 Neutron Separation Energy= Energy needed to liberate a neutron from the Nucleus
-:=<math>S_n = B({197 \atop 79} Au_{118})-B({{196} \atop 79} Au_{117})</math>
+:=<math>S_n = B({138 \atop 56} Au_{118})-B({{136} \atop 55} Au_{117})</math>
 :<math>\left [79(1.007825 u) + 118 (1.008665 u) - 196.97 u\right ] \frac{931.5 MeV}{u} -\left [79(1.007825 u) + 117 (1.008665 u) - 195.967 u\right ] \frac{931.5 MeV}{u}</math>
 :<math>=\left [(1.008665 u) - 196.9665516 u+ 195.9665513 u\right ] \frac{931.5 MeV}{u} = 5.3 MeV</math>