Difference between revisions of "Anisotropic n's vs. isotropic ones"

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==U Photo-fission Cross Section==
 
==U Photo-fission Cross Section==
  
[[File:U235 sigma 01.png | 1000 px]]
 
  
[[File:U238 sigma 01.png | 1000 px]]
+
[[File:U235.sigma.01.png | 1000px]]
 +
 
 +
[[File:U235.sigmaflux.01.png | 1000px]]

Revision as of 20:16, 26 June 2011

go back


Winhold and Halpern, Phys.Rev. 103 4, 990 (1956)

The observation were consistent with the assumption that
anisotropic fission is due solely to photons with-in about
3 MeV of the fission threshold".


The photons in the giant resonance region were found
to produce essentially isotropic fission


Winhold fig.4.png

Anisotropic n's vs. isotropic ones

Say, we have only anisotropic neutrons

[math]\Theta=90^o,\ \phi = 0^o:\ 100\ n's[/math]
[math]\Theta=90^o,\ \phi = 90^o:\ 125\ n's[/math]

So the calculated asymmetry would be:

[math]A = \frac{125}{100} = 1.25[/math]



Now, say, we have extra 200 isotropic neutrons

[math]\Theta=90^o,\ \phi = 0^o:\ 100\ n's[/math]
[math]\Theta=90^o,\ \phi = 90^o:\ 100\ n's[/math]

So the calculated asymmetry would be:

[math]A = \frac{225}{200} = 1.12[/math]


That really reduce the measured asymmetry. If isotropic neutron's are much more than anisotropic ones we would not be able probably to see any asymmetry. Need to count isotropic and anisotropic neutrons.


Source of anisotropic neutrons:

  • ([math]\gamma[/math],f) channel due to photons with-in about 3 MeV of the fission threshold

Source of isotropic neutrons:

  • ([math]\gamma[/math],f) channel due to photons out of 3 MeV of the fission threshold
  • ([math]\gamma[/math],n) channel? Need to check the angular distribution of neutrons.
  • ([math]\gamma[/math],2n) channel? Need to check the angular distribution of neutrons.

U Photo-fission Cross Section

U235.sigma.01.png

U235.sigmaflux.01.png