Difference between revisions of "2-Neutron Correlation"

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; Now, what neutron singles rate into the detector corresponds to 1 fission per pulse?
 
; Now, what neutron singles rate into the detector corresponds to 1 fission per pulse?
 
* 1 fission per pulse corresponds to 2.3 neutrons/fission = 2.3 neutrons/pulse
 
* 1 fission per pulse corresponds to 2.3 neutrons/fission = 2.3 neutrons/pulse
* The number of neutrons hitting the detector per pulse is found as <math>2.3*\frac{\Delta \Omega}{4\pi} = 0.0198 \frac{neutrons hitting detector}{pulse}</math>
+
* The number of neutrons hitting the detector per pulse is found as <math>2.3*\frac{\Delta \Omega}{4\pi} = 0.0198 \frac{neutrons_hitting_detector}{pulse}</math>
  
 
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Revision as of 20:47, 29 May 2012

Big Detector Solid Angle Calculations

MCNPX Simulation
  • 14 MeV neutron source, emitted isotropically ([math]4\pi[/math])
  • Detector placed 1m away from source

Mcnpxsetup.png

  • face of the detector is 15.24cm x 76.2cm, and 3.6cm deep

DetectorDimensions.png

The solid angle can be found from the number of particles hitting the detector as:
[math]\Delta \Omega = 4\pi*\frac{hits}{hits + misses}[/math]

Results
1E9 Neutrons generated
  • 8618287 neutrons hit the detector
  • [math]\Delta \Omega = 0.108 Sr[/math]
As a test to verify our results
We change the detector size to 2cm by 2cm and used 1E9 neutrons again
  • 32061 neutrons struck the detector
  • [math]\Delta \Omega = 0.0004 Sr[/math]
And, as a second test to verify our results
We change the detector size to 1cm by 1cm and used 1E9 neutrons again
  • 7965 neutrons struck the detector
  • [math]\Delta \Omega = 0.0001 Sr[/math]
Now, what neutron singles rate into the detector corresponds to 1 fission per pulse?
  • 1 fission per pulse corresponds to 2.3 neutrons/fission = 2.3 neutrons/pulse
  • The number of neutrons hitting the detector per pulse is found as [math]2.3*\frac{\Delta \Omega}{4\pi} = 0.0198 \frac{neutrons_hitting_detector}{pulse}[/math]

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