05/13/2011 timing test

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Set up like that:

The voltages, thresholds and widths are:

	PMT voltage, V	threshold, mV	discr. width, ns
PS1	-1000	-80	50
PS1	-1000	-80	50
n's	-1500	-200	10

Let's do the timing test. The distances are between PS1+PS2 and n's PMT. The time is time difference between PS1(PS2) and n's detector signals

As the distance becomes 10 cm and less the coincidence rate becomes very low. I have:

▫ 10 cm: PS1+PS2+n 11 coinc/98 min, [math](0.11\pm0.03)[/math] coinc/min

▫ 5 cm: PS1+PS2+n 103 coinc/890 min, [math](0.11\pm0.01)[/math] coins/min

▫ 5 cm: PS1 118182 coinc/890 min, [math](2.213\pm0.006)[/math] coins/min

▫ 5 cm: PS2 138573 coinc/890 min, [math](2.595\pm0.007)[/math] coins/min

Below is the plot of measured time as function of distances:

▫ plot for first 10 events (measurements on May 13, 2001)

▫ plot for last 20 events (measurements on May 16, 2001)

▫ combined plot for total 30 events

As we expect the timing is increase as distance does. But there are some saturation region which probably related to back scattering. Here as we approach the back side of detector the fraction of light scattered from back side increases, so the effective distance increases as well and the time drops down.

Let's approximate the points by line excluding the saturation region:

The average speed would be:

[math]v = \frac{1}{p_0} = \frac{1}{0.1425} \approx 7\ \frac{cm}{ns}[/math]

so about 4 times less then speed of ligh.